Question:
1. The females worked less than the males, and the female median is close to Q1.
2. There is a high data value that causes the data set to be asymmetrical for the males.
3. There are significant outliers at the high ends of both the males and the females.
4. Both graphs have the required quartiles.
Answer:
The correct option is;
1. The females worked less than the males, and the female median is close to Q1
Step-by-step explanation:
Based on the given data, we have;
For males
Minimum = 0
Q1 = 1
Median or Q2 = 20
Q3 = 25
Maximum = 50
For females;
Minimum = 0
Q1 = 5
Median or Q2 = 6
Q3 = 10
Maximum = 18
Therefore, the values of data that affect the statistical measures of spread and center are that
The females worked less than the males as such the statistical data for the females have less variability than the males in terms of interquartile range
Also the female median is very close to Q1, therefore it affects the definition of a measure of center.
Answer:
x/-9 = -16 ; 144
Step-by-step explanation:
x is the variable for "a number". It is being divided by -9, so x must be divided by -9. The number divided by -9 equals -16, so -16 must go on the other side of the equation. To solve, multiply both sides by -9 to cancel out the fraction and isolate the variable.
I think it would be 54 degrees
Answer:
The answer to the nearest tenth is 8.2
Step-by-step explanation:
In order to find the distance between any two points, you must use the distance formula. when you plug in the points into the formula you end up with 8.246, rounded to the nearest tenth would be 8.2. I hope this helps!
Answer:
Step-by-step explanation:
Slope m = (-8-2)/(1+1)=-10/2 = -5
Perpendicular slope-1/m = -1/-5 = 1/5
Equation of a line with perpendicular slope is
y-y1=(-1/m)(x-x1)
y - 2 = (1/5)(x+1)
y =2 +(1/5)(x+1)
