Answer:
is the imaginary line where you could fold the image and have both halves match exactly.
You didn’t show us the answers we can choose, how do we solve it then
1. To solve this exercise, you must apply the formula for calculate the area of a trapezoid, which is shown below:
<span>
A=(b1+b2/2)h
</span><span>
A is the area of the trapezoid.
</span><span> b1 is the larger base of the trapezoid (b1=16-4=12 ft).
</span><span> b2 is the smaller base of the trapezoid (b2=10-4=6 ft).
</span><span> h is the height of the trapezoid (h=12-4=8 ft)
</span><span>
2. When you substitute these values into the formula A=(b1+b2/2)h, you obtain:
</span><span>
A=(b1+b2/2)h
</span><span> A=(12 ft+6 ft/2)(8 ft)
</span><span> A=9 ftx8ft
</span><span> A=72 ft²
</span><span>
3. </span><span>The length of fencing is:</span> a²=b²+c² a=√b²+c² a=√(8 ft)²+(6 ft)² a=10 ft Perimeter (Length of fencing)=12 ft+8 ft+6 ft+10 ft=36 ft
