Hello :
hello : <span>
1 ) if : x</span>ـــــــ> ± ∞
<span>
limf(x) = b ....(b</span>∈R) so : y=b is the equation of
the line horizontal asymptote.
<span>
2) if : x</span>ـــــــ>
a ...(a∈R)<span>
limf(x) = ± ∞
<span>so : x=a is the equation of the
line vertical asymptote.</span></span>
<span><span>hint : in this exercice : a = 2 or a = 7 but : b=2</span></span>
Answer:
The probability that at least one is a boy is 0.525
Step-by-step explanation:
P(Baby being a girl) = 0.475
Now, if A is any arbitrary event . Then:
as we know P(A)+ P(not A) = 1
⇒ P(A not happening) = 1 - P(A event happening)
Also, P( baby not being a girl) = P(baby being a boy)
So, P(baby being a boy) = 1 - P( baby being a girl)
= 1 - 0.475 = 0.525
Hence, the probability that at least one is a boy is 0.525
Answer:
m∠ABD = 88º
m∠CBD = 23º
Step-by-step explanation:
(-10x + 58) + (6x + 41) = 111
Combine like terms
-4x + 99 = 111
Subtract 99 from both sides
-4x = 12
Divide both sides by -4
x = -3
------------------------
m∠ABD = -10x + 58
m∠ABD = -10(-3) + 58
m∠ABD = = 30 + 58
m∠ABD = 88º
m∠CBD = 6x + 41
m∠CBD = 6(-3) + 41
m∠CBD = -18 + 41
m∠CBD = 23º
