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2 years ago

I don't understand this and I can only miss 1 question on my quiz and already did

Mathematics

2 answers:

Dahasolnce [82]2 years ago

7 0

Answer:

Step-by-step explanation:

they add five

9+5=14

12+5=17

15+5=20

18+5=23

miv72 [106K]2 years ago

6 0

It’s 23 I think fhgdgdfkbbbvff

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Find the distance between the points (-1,-7) and (8,-9). The answer must be a whole number or a fully simplified radical express

ruslelena [56]

Answer:

The answer is

<h2> $\sqrt{85} \: \: \: units$ </h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-1,-7) and (8,-9)

The distance between them is

$d = \sqrt{( { - 1 - 8})^{2} + ({ - 7 + 9})^{2} } \\ = \sqrt{ ({ - 9})^{2} + {2}^{2} } \\ = \sqrt{81 + 4}$

We have the final answer as

$\sqrt{85} \: \: \: units$

Hope this helps you

3 0

3 years ago

Solve with quadratic formula. 4k^2- 20 = k

zvonat [6]

Answer: $k= \frac{1+\sqrt{321} }{8} , \frac{1-\sqrt{321} }{8}$

Step-by-step explanation:

Move all terms to one side.

$4^{2} -20-k=0$

Use the Quadratic Formula.

$k=\frac{1+\sqrt{321} }{8}$ , $k=\frac{1-\sqrt{321} }{8}$

5 0

3 years ago

Read 2 more answers

Guys omg please someone answer this asap this is due tmmr

MrRissso [65]

Answer:

First, break the shape into smaller shapes.

Bigger rectangle: 5m, 8m

Thin rectangle: 7m, 3m

Thinner rectangle: 8m, 2m

We will call the bigger rectangle B, the thin rectangle R, and the thinner rectangle r.

Step-by-step explanation:

B = 8 • 5 = 40

R = 7 • 3 = 21

r = 2 • 8 = 16

Add the areas together:

40 + 21 + 16 = 77

Therefore, the area is 77 meters.

4 0

2 years ago

Which if the following rules best describes the matrix below?

goldfiish [28.3K]

i think A because delation of scale factor 2

5 0

3 years ago

Read 2 more answers

Given the following right triangle, find cose, sine, tane sececsce, and cote. Do not

IgorLugansk [536]

Step-by-step explanation:

Use the Pythagorean theorem:

$leg^2+leg^2=hypotenuse^2$

We have

$leg=4,\ hypotenuse=10$

Substitute:

$4^2+leg^2=10^2$

$16+leg^2=100$ subtract 16 from both sides

$leg^2=84\to leg=\sqrt{84}\\\\leg=\sqrt{(4)(21)}\\\\leg=\sqrt4\cdot\sqrt{21}\\\\leg=2\sqrt{21}$

$sine=\dfrac{opposite}{hypotenuse}\\\\cosine=\dfrac{adjacent}{hypotenuse}\\\\tangent=\dfrac{opposite}{adjacent}\\\\cotangent=\dfrac{adjacent}{opposite}\\\\secant=\dfrac{hypotenuse}{adjacent}\\\\cosecant=\dfrac{hypotenuse}{opposite}$

Substitute:

$hypotenuse=10,\ opposite=4,\ adjacent=2\sqrt{21}$

$\sin\theta=\dfrac{4}{10}=\dfrac{2}{5}\\\\\cos\theta=\dfrac{2\sqrt{21}}{10}=\dfrac{\sqrt{21}}{5}\\\\\tan\theta=\dfrac{4}{2\sqrt{21}}=\dfrac{2}{\sqrt{21}}\cdot\dfrac{\sqrt{21}}{\sqrt{21}}=\dfrac{2\sqrt{21}}{21}\\\\\cot\theta=\dfrac{2\sqrt{21}}{4}=\dfrac{\sqrt{21}}{2}\\\\\sec\theta=\dfrac{10}{2\sqrt{21}}=\dfrac{5}{\sqrt{21}}\cdot\dfrac{\sqrt{21}}{\sqrt{21}}=\dfrac{5\sqrt{21}}{21}\\\\\csc\theta=\dfrac{10}{4}=\dfrac{5}{2}$

5 0

3 years ago

I don't understand this and I can only miss 1 question on my quiz and already did​

I don't understand this and I can only miss 1 question on my quiz and already did