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3 years ago

Buying three tires at $80 each and getting a fourth tire free

Mathematics

1 answer:

kykrilka [37]3 years ago

4 0

Answer

3 x 80=240

240 / 4=$60 effective unit rate for each tire.

Step-by-step explanation:

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I need help asap someone please help me i dont understand this question so can someone help me

eduard

Answer:

we conclude that:

$\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}=\frac{1}{2p^3-p^2}$

Step-by-step explanation:

Given the expression

$\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}$

$=\frac{2p}{4p^2-1}\times \frac{6p+3}{6p^3}$

$=\frac{2p}{4p^2-1}\times \frac{2p+1}{2p^3}$

$\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}$

$=\frac{2p\left(2p+1\right)}{\left(4p^2-1\right)\times \:2p^3}$

cancel the common factor: 2

$=\frac{p\left(2p+1\right)}{\left(4p^2-1\right)p^3}$

cancel the common factor: p

$=\frac{2p+1}{p^2\left(4p^2-1\right)}$

$=\frac{2p+1}{p^2\left(2p+1\right)\left(2p-1\right)}$

cancel the common factor: 2p+1

$=\frac{1}{p^2\left(2p-1\right)}$

Expanding

$=\frac{1}{2p^3-p^2}$

Thus, we conclude that:

$\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}=\frac{1}{2p^3-p^2}$

7 0

2 years ago

PLEASE HELP!!!!!!!<br> will mark brainliest!!!!

Setler [38]

15.25. hope this helps

4 0

2 years ago

Three salesmen work for the same company, selling the same product. And, although they are all paid on a weekly basis, each sale

Korvikt [17]

Answer:

Week 1

Step-by-step explanation:

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2 years ago

Read 2 more answers

Which graph represents y = StartRoot x minus 4 EndRoot?

ozzi

The answer is for a fact c

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1 year ago

A manufacturing process produces bags of cookies. The distribution of content weights of these bags is Normal with mean 15.0 oz

NeTakaya

Answer:

100 bags

Step-by-step explanation:

S.E = σ/ √n

0.1 = 1 / √n

Square both sides

0.1² = 1² / n

0.01 = 1 / n

0.01n = 1

n = 1 / 0.01

n = 100

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2 years ago