Part A) Find BC, the distance from Tower 2 to the plane, to the nearest foot.
in the triangle ACD
sin16=CD/(7600+BD)--------> CD=sin16*(7600+BD)---------> equation 1
in the triangle BCD
sin24=CD/BD-----------> CD=sin24*BD---------------> equation 2
equation 1=equation 2
sin16*(7600+BD)=sin24*BD-----> sin16*7600+sin16*BD=sin24*BD
sin24*BD-sin16*BD=sin16*7600----> BD=[sin16*7600]/[sin24-sin16]
BD=15979 ft
in the triangle BCD
cos24=BD/BC---------> BC=BD/cos24-------> 15979/cos24-------> 17491
BC=17491 ft
the answer part 1) BC is 17491 ft
Part 2) Find CD, the height of the plane from the ground, to the nearest foot.
CD=sin24*BD ( remember equation 2)
BD=15979 ft
CD=sin24*15979 -----------> CD=6499 ft
the answer part 2) CD is 6499 ft
The solutions to the respective equations shown in the image are 220, 41, -52, 1.385 and 11
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more numbers and variables.
a) 23 + (-16) + 42 * 5 - (-3)
= 23 - 16 + 210 + 3 = 220
b) -6(12 - 15) + 23
= -6(-3) + 23 = 18 + 23
= 41
c) -50 + (-10) + (5 - 3)4
= -50 - 10 + 2(4) = -50 - 10 + 8
= -52
d) -4.5 (-0.53) + (-1)
= 2.385 - 1
= 1.385
e) 5 - 2 + 8
= 3 + 8
= 11
The solutions to the respective equations shown in the image are 220, 41, -52, 1.385 and 11
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Answer:
Statement: AB=CD, BC=AD
Reason: By definition of parallelogram .
Statement: AC=AC
Reason: Reflexive property of equality.
Step-by-step explanation:
1.Statement:
.
Reason: For parallel lines cut by a transversal , corresponding angles are congruent.
2.Statement:AB=CD,BC=AD
Reason: By definition of parallelogram.
3.Statement: AC=AC
Reason: Reflexive property of equality.
4.Statement:
.
Reason: SSS criterion for congruence.
5.Statement:
.
Reason: Given .
6.Statement:
.
Reason: By definition of parallelogram.
7.Statement:
.
Reason: Alternate Interior Angles Theorem.
What’s the question ? & need additional information
Total students = 15+21=36, so the probability of choosing a girl is 21/36, which reduces to 7/12.
Total freshmen = 12+15=27, so the probability of choosing a freshman is 27/36, which reduces to 3/4.