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2 years ago

How can 65% be broken down with friendly percents to find 65% of a number?

Mathematics

2 answers:

riadik2000 [5.3K]2 years ago

5 0

Answer:

given that the only one that actually adds up to 65%

is B....

B. 25% + 10% + 10% + 10% + 10%

Step-by-step explanation:

zhannawk [14.2K]2 years ago

4 0

Answer:

10%

Step-by-step explanation:

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Brainliest for correct awnser! What is the domain of f(x)?

Marina86 [1]

Answer:

$\mathrm{B.}$ All real numbers except x = 2, x = 5

Step-by-step explanation:

If the denominator is equal to 0 then the function would be undefined.

Set the denominator equal to 0.

x² - 7x + 10 = 0

Factor the left side of the equation.

(x - 5)(x - 2) = 0

Set the factors equal to 0.

x - 5 = 0

x = 5

x - 2 = 0

x = 2

The domain is all real numbers except x = 2 and x = 5.

5 0

2 years ago

The mean and the median are the same.<br> 2,3,4,5

Ber [7]

Step-by-step explanation:

$mean \: ( \bar x) = \frac{2 + 3 + 4 + 5}{4} = \frac{14}{4} = 3.5 \\ \\ median \: = \frac{3 + 4 }{2} = \frac{7}{4} = 3.5 \\ \\$

Thus, mean and median are same.

7 0

2 years ago

Cherries cost $5 for 2 pounds and $7.50 for 3 pounds. Question: a. What is the cost per pound? b. Is it constant? c. If you were

Fittoniya [83]

A. 1 pound of cherries costs 2.50

B. Yes it is constant

C. I believe that you would put cost on the y and lbs on the x
E. 5 lbs of cherries = 2.50 x 5 = $12.50

8 0

2 years ago

A box of donuts containing 6 maple bars, 3 chocolate donuts, and 3 custard filled donuts is sitting on a counter in a work offic

Svetlanka [38]

Probabilities are used to determine the chances of selecting a kind of donut from the box.

The probability that Warren eats a chocolate donut, and then a custard filled donut is 0.068

The given parameters are:

$\mathbf{Bars = 6}$

$\mathbf{Chocolate = 3}$

$\mathbf{Custard= 3}$

The total number of donuts in the box is:

$\mathbf{Total= 6 + 3 + 3}$

$\mathbf{Total= 12}$

The probability of eating a chocolate donut, and then a custard filled donut is calculated using:

$\mathbf{Pr = \frac{Chocolate}{Total}\times \frac{Custard}{Total-1}}$

So, we have:

$\mathbf{Pr = \frac{3}{12}\times \frac{3}{12-1}}$

Simplify

$\mathbf{Pr = \frac{3}{12}\times \frac{3}{11}}$

Multiply

$\mathbf{Pr = \frac{9}{132}}$

Divide

$\mathbf{Pr = 0.068}$

Hence, the probability that Warren eats a chocolate donut, and then a custard filled donut is approximately 0.068