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vaieri [72.5K]
2 years ago
15

How can 65% be broken down with friendly percents to find 65% of a number?

Mathematics
2 answers:
riadik2000 [5.3K]2 years ago
5 0

Answer:

given that the only one that actually adds up to 65%

is B....

B. 25% + 10% + 10% + 10% + 10%

Step-by-step explanation:

zhannawk [14.2K]2 years ago
4 0

Answer:

10%

Step-by-step explanation:

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3(2c+d)-4(c-d)+d squared when c=1 d=3<br> please explain steps
steposvetlana [31]

Answer:

3(2c+d)-4(c-d)+d^2.

6c+3d-(4c+4d)+d^2.

6×1+3×3-4×1+4×3+9.

6+9-4+12+9=32.

4 0
3 years ago
At a particular restaurant each mozzarella stick has 90 cal in each pizza roll has 80 cal. A combination meal with the mozzarell
serious [3.7K]

Answer:

The meal consist 11 mozzarella sticks and 6 pizza rolls.

Step-by-step explanation:

We are given the following in the question:

Calories in mozzarella stick = 90

Calories in pizza roll = 80

Let x be the number of a mozzarella stick and y be the number of pizza rolls.

Total calories in meal = 1470

Thus, we can write the equation:

90x + 80y = 1470

There are five more mozzarella sticks than pizza roll.

Thus, we can write the equation:

x = y + 5\\x-y = 5

Solving the two equations, we get,

90x+80y+80x-80y = 1470 + 400\\170x = 1870\\x = 11\\y = 11-5 = 6

Thus, the meal consist 11 mozzarella sticks and 6 pizza rolls.

4 0
2 years ago
27. Solve for x?<br><br> A 25 <br> B 16 <br> C 27<br> D 9
musickatia [10]
I’m not really sure but if I did it correctly I’m pretty sure it’s c.27
8 0
3 years ago
Brian works in the lab and feels an empty cylindrical flask with 200 cubic centimeters of liquid. The flask has a radius of 3 cm
Fittoniya [83]

Answer:

<h2>49.49%</h2>

Step-by-step explanation:

volume of liquid in the flask= 200 cm^3

radius of the flask = 3 cm

height of the  flask= 12 cm

volume of flask is given by =

putting values and solving we get =396 cm^3

therefore the volume unfilled= 396-200= 196cm^3

therefore % of volume unfilled= 196/396*100= 49.49%

6 0
3 years ago
A particle is projected with a velocity of <img src="https://tex.z-dn.net/?f=40ms%5E-%5E1" id="TexFormula1" title="40ms^-^1" alt
Katena32 [7]

Answer:

2\sqrt{55}\text{ m/s or }\approx 14.8\text{m/s}

Step-by-step explanation:

The vertical component of the initial launch can be found using basic trigonometry. In any right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. Let the vertical component at launch be y. The magnitude of 40\text{ m/s} will be the hypotenuse, and the relevant angle is the angle to the horizontal at launch. Since we're given that the angle of elevation is 60^{\circ}, we have:

\sin 60^{\circ}=\frac{y}{40},\\y=40\sin 60^{\circ},\\y=20\sqrt{3}(Recall that \sin 60^{\circ}=\frac{\sqrt{3}}{2})

Now that we've found the vertical component of the velocity and launch, we can use kinematics equation v_f^2=v_i^2+2a\Delta y to solve this problem, where v_f/v_i is final and initial velocity, respectively, a is acceleration, and \Delta y is distance travelled. The only acceleration is acceleration due to gravity, which is approximately 9.8\:\mathrm{m/s^2}. However, since the projectile is moving up and gravity is pulling down, acceleration should be negative, represent the direction of the acceleration.

What we know:

  • v_i=20\sqrt{3}\text{ m/s}
  • a=-9.8\:\mathrm{m/s^2}
  • \Delta y =50\text{ m}

Solving for v_f:

v_f^2=(20\sqrt{3})^2+2(-9.8)(50),\\v_f^2=1200-980,\\v_f^2=220,\\v_f=\sqrt{220}=\boxed{2\sqrt{55}\text{ m/s}}

3 0
3 years ago
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