Graph the line that represents this equation:<br> y = -5.1 +2

Given a data set has a Median of 10 and an Inner Quartile Range of 5, what is the range of values that Q3 could possibly be?

Elanso [62]

Because the Median could be anywhere within the interquartile range the upper quartile could be between 10 and 15

5 0

3 years ago

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A coin is tossed 20 times. It lands heads 4 times. Compare the experimental probability to its theoretical probability. It the p

Lubov Fominskaja [6]

The theoretical probability is how many times it SHOULD land on heads. Since there is two sides, the theoretical l probability says it should land on heads 10 times out of 20 or 1/2. The experimental probability can vary, it is how many times it ACTUALLY lands on heads when you test it. In this case it landed on heads 4 times out of 20 or 1/5 of the time. For this problem, the experimental probability is less than the theoretical probability.<span />

7 0

4 years ago

Find sec(2Arcsin (-1/3))

gavmur [86]

<span>Think of arcsin (-1/3) as an angle, and call it "theta." The the original problem becomes "find sec [ 2 theta ]"
1 1
which is the same as "find ------------------ " or --------------------------------------
cos[2 theta] (cos theta)^2 - (sin theta)^2

Recall that theta = the angle whose sine is -1/3. Thus, sin theta = -1/3 and cos theta = 2sqrt(2) / 3.

So we now have:

1
-------------------------------------------
2 sqrt(2) -1
[------------------- ]^ 2 - [ ------- ]^2
3 3

which boils down to:

1 1
----------------- = ---------------- = 9/7 (answer)
8 1 7/9
------ - --------
9 9

</span>

4 0

4 years ago

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Prove that if one solution for a quadratic equation of theform x2 + bx + c = 0 is rational (where b and c are rational),then the

Elenna [48]

Answer:

The other solution of the given equation x² + bx + c = 0 is also rational number.

Step-by-step explanation:

Here, given: ax² + bx + c = 0 is a quadratic equation

Also, one solution (r) of equation is RATIONAL.

To show: The other solution (s) is also RATIONAL

Now, here: as x² + bx + c = 0

Since r and s are the two given solutions, the given equation can be factorized as:

x² + bx + c = (x -r) (x - s)

Simplifying LHS, we get:

(x -r) (x - s) = x x - r (x) - s (x) + (r)(s)

= x² + x(-r - s) + rs

or, x² + bx + c = x² + x(-r - s) + rs

Comparing the related terms, we get:

b = (-r - s)

⇒ b + s = - r

or, s = -r - b

Now, given : r = Rational and the negative of a rational is also rational.

⇒ -r is also rational

Also, difference of two rational number is also rational.

⇒ -r - b is also rational

⇒ s is a RATIONAL NUMBER

Hence, the other solution of the given equation x² + bx + c = 0 is also rational number.

7 0

4 years ago

I need the answers to 11 12 and 13

kodGreya [7K]

Answer:

11. x= 117 and y =57

12. 9

13. 900 degrees

Step-by-step explanation:

11. Y can be found using supplementary angles. 123+y = 180 since they form a straight line. This means y=57. The inside of a quadrilateral is equal to 360 degrees. This means 117+69+57 +x=360. Then 243+x=360 and x= 117.

12. The exterior angles of a polygon with n sides is 360/n. Since we don't know n but we do know the angle is 40 degrees, we write 360/n=40. Solve for n.

360/n=40

360=40n

360/40=n

n= 9

13. This figure is a regular sides polygon. It has 7 sides and therefore 900 degrees.

7 0

4 years ago

Graph the line that represents this equation: y = -5.1 +2