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aev [14]
3 years ago
11

A certain club has 10 members, including Harry. One of the 10 members is to be chosen at random to be the president, one of the

remaining 9 members is to be chosen at random to be the secretary, and one of the remaining 8 members is to be chosen at random to be the treasurer. What is the probability that Harry will be either the member chosen to be the secretary or the member chosen to be the treasurer
Mathematics
1 answer:
devlian [24]3 years ago
7 0

Answer:

The probability that Harry will be chosen as either as Secretary or as treasurer but not as president out of those 10 members will be \frac{1}{5}.

Step-by-step explanation:

We have 10 members out of which one is Harry, we need to choose one of the 10 members as President, one to be as secretary out of the remaining 9, one  as the treasurer of the remaining 8 members.

We want harry to be as either as secretary or as treasurer. so we will consider both the cases

Probability is given by = No of favorable outcomes/ Total no of outcomes

(1) Harry as secretary : If harry is to be chosen as secretary then he can't be a president or he cant be a Treasurer

  As president = \frac{1}{10}

  Not as president = 1 - \frac{1}{10} = \frac{9}{10}

Now he is selected for the secretary so he can't be selected as treasurer.

Not as treasurer = 1

Probability for chosen as secretary = \frac{9}{10}*\frac{1}{9}*1  = \frac{1}{10}  

(2) Harry as treasurer : If harry is to be chosen as the treasurer so he can't be chosen as a President or as a Secretary.

Probability for not chosen as president = \frac{9}{10}

Probability for not chosen as secretary =  1-\frac{1}{9} = \frac{8}{9}

Probability to be chosen as treasurer = \frac{1}{8}

Probability to be chosen as Treasurer = \frac{9}{10}*\frac{8}{9}*\frac{1}{8} = \frac{1}{10}

Total probability for Harry to be chosen as either secretary or as treasurer will be = P(Secretary) +P(Treasurer)

           = \frac{1}{10} +\frac{1}{10}  = \frac{1}{5}

Therefore the probability that Harry will be chosen as either as Secretary or as treasurer but not as president out of those 10 members will be \frac{1}{5}.

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Mariana [72]

The question is incomplete. The map is attached as a photo and here is the complete question:

a. What is the actual distance between Saugerties and

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b. Catskill is 15 miles from Saugerties. What would the

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c. On another map, the distance between Saugerties and

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Since you have asked the answer for part (c) only, here is the answer:

Answer:

<u>The distance from Saugerties to Catskill would be </u><u>3 inches</u><u> on this map.</u>

Step-by-step explanation:

On the given map, the distance between Saugerties and Kingston is 4 inches and the scale is <u>1 inch = 2.5 miles.</u>

To calculate the actual distance in miles between Saugerties and Kingston, consider the given scale:

1 inch ---------- 2.5 miles

4 inches ------ x miles

Cross multiplying:

1x = 2.5 x 4

x = 10 miles

The actual distance between Saugerties and Kingston is 10 miles.

On another map, the distance between Saugerties and Kingston is 2 inches. Which means the scale is 2 inches = 10 miles. So 1 inch = 10/2 = 5 miles

The scale on the other map is 1 inch = 5 miles.

Catskill is 15 miles from Saugerties (given in the previous part). So on the map:

1 inch -------- 5 miles

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Cross multiplying:

15 = 5y

y = 15/5

<u>y = 3 inches.</u>

The distance from Saugerties to Catskill would be 3 inches on this map.

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Step-by-step explanation:

ABC and DEF are not similar transformations the second one is wrong, the third one is wrong because. The last one ios right because by deduction it is.

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Answer:

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