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ruslelena [56]
3 years ago
9

HELP ME WITH THIS! 1/3 a = 7/9

Mathematics
2 answers:
Pachacha [2.7K]3 years ago
8 0

It should be 2 1/3......

andreyandreev [35.5K]3 years ago
6 0

Answer:

a = 2 \frac{1}{3}

Step-by-step explanation:

Given

\frac{1}{3} a = \frac{7}{9}

Multiply both sides by 9 ( the LCM of 3 and 9 ) to clear the fractions

3a = 7 ( divide both sides by 3 )

a = \frac{7}{3} = 2 \frac{1}{3}

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Natali5045456 [20]
4 is the correct answer
4 0
3 years ago
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R varies directly as S and inversely as T. if R = 8 when S = 4 and T = 3, then R is equal to ​
Alex

Answer:

R = 6S/T

Step-by-step explanation:

R ∝ S/ T

》R = kS/ T

》k = RT/ S

If R = 8 when S = 4 and T = 3

then, k = (8 × 3)/ 4

k = 6

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A researcher shows Trey two containers of the same size, both containing the same amount of marbles. The researcher pours one co
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Answer:

Conservation

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3 0
3 years ago
Find thhe remainder when 7^203 is divided by 4
Aleksandr [31]
Using the square-and-multiply approach, we have

7^{203}=7\times(7^{101})^2
7^{101}=7\times(7^{50})^2
7^{50}=(7^{25})^2
7^{25}=7\times(7^{12})^2
7^{12}=(7^6)^2
7^6=(7^3)^2
7^3=7\times7^2

and so, using the property that, if a_1\equiv b_1\mod n and a_2\equiv b_2\mod n, then a_1a_2\equiv b_1b_2\mod n, we get

7\equiv3\mod4
7^2\equiv9\equiv1\mod4
7^3\equiv7\times1\equiv7\equiv3\mod4
7^6\equiv9\equiv1\mod4
7^{12}\equiv1\mod4
7^{25}\equiv7\times1\equiv7\equiv3\mod4
7^{50}\equiv9\equiv1\mod4
7^{101}\equiv7\times1\equiv7\equiv3\mod4
7^{203}\equiv7\times9\equiv3\times1\equiv3\mod4
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3 years ago
Consider a sequence whose first five terms are: -3,0,3, 24, 81.
vfiekz [6]
D is the correct answer
6 0
3 years ago
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