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MAVERICK [17]
3 years ago
9

PLZ HELP NOW PLZ PLZ

Mathematics
1 answer:
anyanavicka [17]3 years ago
7 0

Answer:

16ft i think

Step-by-step explanation:

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Write the product in its simplest form:<br> -4y²• 8y4
denpristay [2]
-128y^2 x y^1 +2 = -128y^3
8 0
2 years ago
Which could you use to prove triangle AED is congruent to triangle CEB?
Hunter-Best [27]

Answer:

Option (C)

Step-by-step explanation:

Given:

In right triangles ΔAED and CEB,

m∠AED = m∠CEB = 90°

DE ≅ BE

AD ≅ BC

To prove:

ΔAED ≅ ΔCEB

                    Statements                         Reasons

1). m∠AED = m∠BC = 90°              1). Given

2). DE = BE                                     2). Given

3). AD = BC                                    3). Given

4). ΔAED ≅ ΔCEB                          4). By HL theorem of congruence

Option (C) is the answer.

4 0
3 years ago
PLEASE HELP
lisabon 2012 [21]

Step-by-step explanation:

The figure below shows a portion of the graph of the function j\left(x\right) \ = \ 4^{x-2}, hence the average rate of change (slope of the blue line) between the x and x+h is

                     \text{Average rate of change} \ = \ \displaystyle\frac{\Delta y}{\Delta x} \\ \\ \rule{3.7cm}{0cm} = \dsiplaystyle\frac{f\left(x+h\right) \ - \ f\left(x\right)}{\left(x \ + \ h \right) \ - \ x} \\ \\ \\  \rule{3.7cm}{0cm} = \displaystyle\frac{f\left(x + h\right) \ - \ f\left(x\right)}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{4^{x+h-2} \ - \ 4^{x-2}}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{4^{x-2+h} \ - \ 4^{x-2}}{h}

                                                            \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{\left(4^{x-2}\right)\left(4^{h}\right) \ - \ 4^{x-2}}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{\left(4^{x-2}\right)\left(4^{h} \ - \ 1 \right)}{h}

7 0
2 years ago
3x +15= 2x + 10 + x +5 how many solutions​
Travka [436]

3x +15= 2x + 10 + x +5\\\\3x-2x-x=  10  +5-15\\\\0=0

infinitely many solutions

6 0
3 years ago
Help me plz and explain this a grade!!!
77julia77 [94]
Part 1: should be C. Because the question said 1.2 added to a number.

Part 2:16.8
4 0
3 years ago
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