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bekas [8.4K]
3 years ago
11

Item 8 A dog is leashed to the corner of a house. How much running area does the dog have? Round your answer to the nearest squa

re foot, if necessary. The dog has about square feet of running area.
Mathematics
1 answer:
Scilla [17]3 years ago
7 0

Complete Question:

A dog is leashed to the corner of a house with a 15 foot leash. How much running area does the dog have? Round your answer to the nearest square foot.

Answer:

The dog has about 707 square feet of running area.

Step-by-step explanation:

From the illustration in the question, one can conclude that the dog can travel in a circular path.

So, the length of the leash represents the radius and we are to calculate the required area using the area of a circle.

We have:

Radius = 15ft

Area = \pi r^2

Where

r = Radius = 15 and \pi = 3.14

So:

Area = 3.14 * 15^2

Area = 3.14 * 225

Area = 706.5ft^2

Area = 707\ ft^2

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Mary is going for a walk. She walks 12.5 miles in 5 hours. What is her speed
xz_007 [3.2K]

To find her speed, divide the total distance by the total time:

12.5 miles / 5 hours = 2.5 miles per hour.

3 0
3 years ago
( simultaneous equations)
daser333 [38]

Answer:

See method below.

Step-by-step explanation:

m/n + n/3 = 2

2/m + n = 4    

First  eliminate the fractions by multiplying the first equation by 3n:-

3m + n^2 = 6n...........(1)

and the second equation by m:-

2 + mn = 4m..............(2)

Now we solve using substitution:-

From equation  (2):-

4m - mn = 2

m = 2 / (4 - n)

Now substitute for m in equation (1):-

6/ (4 - n) + n^2 = 6n

6 + n^2(4 - n) = 6n(4 - n)

6 + 4n^2 - n^3 = 24n - 6n^2

n^3 - 10n^2 + 24n - 6 = 0

This will not factor so we could solve this using graphical software.

To find the values of the variable m we substitute the found values of n into one of the original equations and solve for m.






6 0
3 years ago
The product of 5p2q and -4p3q4 is
Nitella [24]

Answer:

-20p^5q^5

Step-by-step explanation:

20p^5q^5 that's your answer

5 0
2 years ago
a block of gold with a mass of 4,830 kilograms has a volume of 0.25 cubic meters. what is the density of the gold?
GrogVix [38]
Density = mass / volume
Density = 4,830 / 0.25
Density = 19,320 kg/m
8 0
3 years ago
What will the population of bacteria be if I have 225 bacteria to start and it triples ever hour for 2 hours
VMariaS [17]

225•3=675

675•3=2,025

675+2,025=2700

The answer is 2,700.

Hope this helps!

4 0
3 years ago
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