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Viktor [21]
3 years ago
15

Please help me:( I've been stuck on this for so long

Mathematics
2 answers:
Contact [7]3 years ago
6 0

Answer:\

S=4

Step-by-step explanation:

Hope this helped!!!!!

Sladkaya [172]3 years ago
4 0

Answer:

s=4

Step-by-step explanation:

3/4 s - 5/4 = s/8 +5/4

Multiply the equation by 8 to get rid of the fractions

8*(3/4 s - 5/4) =8( s/8 +5/4)

6s - 10 = s +10

Subtract s from each side

6s -s -10 s-s +10

5s -10 = 10

Add 10 to each side

5s-10+10 =10+10

5s= 20

Divide each side by 5

5s/5 = 20/5

s =4

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Step-by-step explanation:

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3 years ago
The diagonals of a rhombus are 14 and 48cm. Find the length of a side of the rhombus.
FromTheMoon [43]

Step-by-step explanation:

Let ABCD be a rhombus. So, AC (AC = 14 cm) and BD (BD=48 cm) will be its diagonals. Let us assume that diagonals are intersecting at point O.

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\because \: OA  =  \frac{1}{2}  \times AC \\  \\   \therefore \: OA  =  \frac{1}{2}  \times 14 \\  \\   \huge \red{ \boxed{\therefore \: OA  =  7 \: cm}} \\  \\ \because \: OB  =  \frac{1}{2}  \times BD \\  \\ \therefore \: OB  =  \frac{1}{2}  \times 48 \\  \\ \huge \red{ \boxed{\therefore \: OB  = 24 \: cm}} \\  \\ In \:  \triangle OAB, \:  \:  \angle AOB=90° \\  \therefore \: by \: Pythagoras \: Theorem \\ AB= \sqrt{OA^2 +OB^2 }  \\  =  \sqrt{7^2 +24^2 } \\ =  \sqrt{49+576 } \\ =  \sqrt{625 } \\  \huge \orange{ \boxed{\ \therefore \:AB= 25 \: cm.}}

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3 0
4 years ago
Solve for x: 6x + 1/4 (4x + 3) &gt; 12<br> Ox&gt;<br> 10<br> 7<br> Ox&gt; 2<br> ox= 10<br> X = 2
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Given:

The inequality is:

6x+\dfrac{1}{4}(4x+3)>12

To find:

The values for x.

Solution:

We have,

6x+\dfrac{1}{4}(4x+3)>12

Using distributive property, we get

6x+\dfrac{1}{4}(4x)+\dfrac{1}{4}(3)>12

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x>\dfrac{45}{7\times 4}

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Therefore, the required solution is x>\dfrac{45}{28}.

Note: All options are incorrect.

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marusya05 [52]

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