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3 years ago

Use the Rational Zeros Theorem to write a list of all potential rational zeros.

Mathematics

1 answer:

allochka39001 [22]3 years ago

6 0

Answer:

Your potential zeros are ± 1/2, ± 3/2, ± 1, and ± 2.

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Marina CMI [18]

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3 years ago

The concentration of dichlorodiphenyltrichloroethane (DDT - an infamous pesticide) in Lake Michigan has been declining exponenti

mojhsa [17]

Answer: A) $y=13e^{-0.1359t}$

B) H = 5.10

C) Yes

Step-by-step explanation: Exponential Decay function is a model that describes the reducing of an amount by a constant rate over time. Generally, it is written in the form: $y(t)=Ce^{rt}$

A) C is initial quantity, in this case, the initial concentration of DDT. To determine r, using the data given:

$y(t)=Ce^{rt}$

$2.22=13e^{13r}$

$e^{13r}=0.1708$

Using a natural logarithm property called power rule:

$13r=ln(0.1708)$

$r=\frac{ln(0.1708)}{13}$

$r=-0.1359$

The decay function for concentration of DDT through the years is $y(t)=13e^{-0.1359t}$

B) The value of H is calculated by $y=C(0.5)^{\frac{t}{H} }$

$2.22=13(0.5)^{\frac{13}{H} }$

$(0.5)^{\frac{13}{H} }=0.1708$

Again, using power rule for logarithm:

$\frac{13}{H} log(0.5)=log(0.1708)$

$\frac{13}{H} =\frac{log(0.1708)}{log(0.5)}$

$\frac{13}{H} =2.55$

H = 5.10

Constant H in the half-life formula is H=5.10

C) Using model $y(t)=13e^{-0.1359t}$ to determine concentration of DDT in 1995:

$y(24)=13e^{-0.1359.24}$

y(24) = 0.5

By 1995, the concentration of DDT is 0.5 ppm, so using this model is possible to reduce such amount and more of DDT.

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3 years ago

BCDE is a parallelogram.

kumpel [21]

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3 years ago

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You toss n balls into n bins. for each toss there is a 1/n probability that the ball you toss lands in any one of the bins. afte

defon

Answer:1/n - 2/n= -1/n

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3 years ago

Question 1. What expression represents "the sum of 5 times p and 9, divided by 10"?

tia_tia [17]

Answer:

C and C

Step-by-step explanation:

1) (5P + 9)/10 (C)

2) 2 times N plus 1 (C)

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3 years ago