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Musya8 [376]
3 years ago
11

The expression when b=3 and y= -35b-y​

Mathematics
1 answer:
jekas [21]3 years ago
3 0

Answer:

18

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

<em>b</em> = 3

<em>y</em> = -3

5b - y

<u>Step 2: Evaluate</u>

  1. Substitute in variables:                                                                                     5(3) - -3
  2. Multiply:                                                                                                             15 - - 3
  3. Subtract:                                                                                                            18
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Simplify.<br> In e =<br> In e 2x=<br> In 1 =
Shalnov [3]

Answer:

ln e = 1

ln e 2x = 2x

ln 1 = 0

Step-by-step explanation:

ln e

ln(2.718282) = 1

In e 2x

ln(2.718282)(2)x = 2x

ln 1 = 0

5 0
4 years ago
You are standing 24 feet from the base of a tree. The angle of elevation to the top of the tree is 34 degrees. What is the heigh
JulsSmile [24]

Answer:

16.2feet

Step-by-step explanation:

Using the SOH CAH TOA identity

Given the following

Base side = 24feet

angle of elevation = 34degrees

Required

Height of the tree (opposite)

tan theta = opposite/adjacent

tan 34 = H/24

H = 24tan34

H = 24(0.6745)

H = 16.2feet

Hence the height of the tree is 16.2feet

3 0
3 years ago
The first- and second-year enrollment values for a technical school are shown in the table below: Enrollment at a Technical Scho
pav-90 [236]

Answer:

  • <u><em>The solution to f(x) = s(x) is x = 2012. </em></u>

Explanation:

<u>Rewrite the table and the choices for better understanding:</u>

<em>Enrollment at a Technical School </em>

Year (x)       First Year f(x)      Second Year s(x)

2009                  785                        756

2010                   740                        785

2011                    690                        710

2012                   732                         732

2013                   781                          755

Which of the following statements is true based on the data in the table?

  • The solution to f(x) = s(x) is x = 2012.
  • The solution to f(x) = s(x) is x = 732.
  • The solution to f(x) = s(x) is x = 2011.
  • The solution to f(x) = s(x) is x = 710.

<h2>Solution</h2>

The question requires to find which of the options represents the solution to f(x) = s(x).

That means that you must find the year (value of x) for which the two functions, the enrollment the first year, f(x), and the enrollment the second year s(x), are equal.

The table shows that the values of f(x) and s(x) are equal to 732 (students enrolled) in the year 2012,<em> x = 2012. </em>

Thus, the correct choice is the third one:

  • The solution to f(x) = s(x) is x = 2012.
8 0
3 years ago
Describe the error in the subtraction shown below ​
Gemiola [76]

Answer:

-11x+12

Step-by-step explanation:

(x^2-4x+3)-(x^2+7x-9)

x^2-x^2-4x-7x+3-(-9)

-11x+3+9

-11x+12

8 0
3 years ago
Read 2 more answers
A new car is purchased for 19700 dollars. The value of the car depreciates at
Usimov [2.4K]

Answer:

Step-by-step explanation:

We can plug this into a formula and get

5,500 = 19,700(.9075)^{?}

the .9075 comes from 1 - the depreciation value of 9.25% which converts to .0925 in decimal form.

? is what we are trying to solve for.

We can divide both sides by 19,700 and we get

\frac{55}{197} = (0.9075)^?

so ? is about 13.

6 0
4 years ago
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