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Sonbull [250]
3 years ago
13

Pls help with math ASAP

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
3 0
125.6


Area of a circle = πr^2
Area of circle 1 = 3.14 × 11 × 11
=379.94cm^2
Area of circle 2= 3.14 × 9 ×9
=254.64cm^2
Area of a shaded region
=379.94cm^2 - 254.64cm^2
=125.60cm^2

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Help Pls! I need this fast!
lesya [120]

Answer: 36

Step-by-step explanation:

\overline{AB} \cong \overline{BC} (Triangle ABC is isosceles)

m\angle CAB=m\angle CBA=30^{\circ} (base angles of an isosceles triangle are congruent)

\angle MCB=90^{\circ} (In triangle CMB, angles in a triangle add to 180 degrees)

\angle ACM=30^{\circ} (triangle sum theorem)

MB=24 (30-60-90 triangle CMB)

AB=12 (sides opposite congruent angles in a triangle are congruent)

AB=36 (segment addition postulate)

3 0
2 years ago
We know that a token costs $1.75. If you purchase 10 tokens, you get 2 free tokens. Write and solve an equation to find the appr
Bad White [126]

Answer:

c=(10)($1.75)/12

c=$17.50/12

c=$1.458 which rounds to $1.46 per token

3 0
3 years ago
Given: r and s are intersecting lines. Point P lies on r and s. Point Q lies on r and s , What can you conclude about P and Q? S
sasho [114]
Point p and point Q has to be the same point
7 0
3 years ago
1. A farmer divided a field into 1-foot by 1-foot sections and tested soil samples from 32 randomly selected sections in the fie
Ad libitum [116K]
Part A

Answers:
Mean = 5.7
Standard Deviation = 0.046

-----------------------

The mean is given to us, which was 5.7, so there's no need to do any work there.

To get the standard deviation of the sample distribution, we divide the given standard deviation s = 0.26 by the square root of the sample size n = 32
So, we get s/sqrt(n) = 0.26/sqrt(32) = 0.0459619 which rounds to 0.046

================================================

Part B

The 95% confidence interval is roughly (3.73, 7.67)
The margin of error expression is z*s/sqrt(n)
The interpretation is that if we generated 100 confidence intervals, then roughly 95% of them will have the mean between 3.73 and 7.67

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*5.7/sqrt(32)
ME = 1.974949
The margin of error is roughly 1.974949

The lower and upper boundaries (L and U respectively) are:
L = xbar-ME
L = 5.7-1.974949
L = 3.725051
L = 3.73
and
U = xbar+ME
U = 5.7+1.974949
U = 7.674949
U = 7.67

================================================

Part C

Confidence interval is (5.99, 6.21)
Margin of Error expression is z*s/sqrt(n)
If we generate 100 intervals, then roughly 95 of them will have the mean between 5.99 and 6.21. We are 95% confident that the mean is between those values.

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*0.34/sqrt(34)
ME = 0.114286657
The margin of error is roughly 0.114286657

L = lower limit
L = xbar-ME
L = 6.1-0.114286657
L = 5.985713343
L = 5.99

U = upper limit
U = xbar+ME
U = 6.1+0.114286657
U = 6.214286657
U = 6.21
5 0
3 years ago
6.
denpristay [2]

Answer:

15n=135

Step-by-step explanation:

first, you need to know how much of the total amount is the money needed for soccer balls, to find this you take the amount of a soccer ball and multiple it by the amount of people

14×15=210

then you subtract that from the total amount to get the amount spent on jerseys.

345-210=135

to get the amount of each jersey you take 135 and divide by the amount of people

135÷15=9

4 0
3 years ago
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