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Sonbull [250]
3 years ago
13

Pls help with math ASAP

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
3 0
125.6


Area of a circle = πr^2
Area of circle 1 = 3.14 × 11 × 11
=379.94cm^2
Area of circle 2= 3.14 × 9 ×9
=254.64cm^2
Area of a shaded region
=379.94cm^2 - 254.64cm^2
=125.60cm^2

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C IS THE CORRECT ANSWER




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3 years ago
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PLS HELP ITS MY FINAL EXAM What is the area of the base of the cone below? A cone with height 12 feet and volume 90 feet cubed.
hoa [83]

Answer:

A=22.5\ \text{feet}^2

Step-by-step explanation:

We have,

Height of a cone is 12 feet

Volume of the cone is 90 feet

It is required to find the area of the base of the cone.

The base of a cone is circular in shape.

The formula used to find the volume of a cone is given by :

V=\dfrac{1}{3}\pi r^2 h

here, \pi r^2=A (area of base of cone)

V=\dfrac{1}{3}\times Ah\\\\A=\dfrac{3V}{h}\\\\A=\dfrac{3\times 90}{12}\\\\A=22.5\ \text{feet}^2

So, the area of the base of the cone is 22.5\ \text{feet}^2.

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3 years ago
Sequences and Series precalc multiple choice, will give brainliest.
Gala2k [10]

9514 1404 393

Answer:

  False

Step-by-step explanation:

The given formula is the "explicit" formula for the sequence.

The recursive formula would be ...

  a[1] = 160

  a[n] = 1/2·a[n-1] . . . . each term expressed in as a function of previous terms

The given statement is false.

8 0
2 years ago
*Mastery Check. DO NOT ask for help. Find the area of the sector. Round your answer to the nearest tenth.
Juliette [100K]

The area of the sector is 472.6 ft²

<h3>Area of a Sector</h3>

For finding the area of the sector, you need apply the formula:

A=\pi r^2* \frac{\alpha }{360}, where:

r= radius

α= central angle

The question gives:

r= radius= 19 ft

α= central angle = 150°

Thus, the area of the sector will be:

A=\pi r^2* \frac{\alpha }{360}=\pi *19^2*\frac{150}{360} =472.6

Read more about the area of a sector here:

brainly.com/question/22972014

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3 0
2 years ago
Pleaseee someone help me :( Ive been stuck on this for an hour
Whitepunk [10]

Answer:

The number of times organism B's population is larger than organism A's population after 8 days is 32 times

Step-by-step explanation:

The population of organism A doubles every day, geometrically as follows

a, a·r, a·r²

Where;

r = 2

The population after 5 days, is therefore;

Pₐ₅ = = 32·a

The virus cuts the population in half for three days as follows;

The first of ta·2⁵ he three days = 32/2 = 16·a

The second of the three days = 16/2 = 8·a

After the third day, Pₐ = 8/2 = 8·a

The population growth of organism B is the same as the initial growth of organism A, therefore, the population, P₈ of organism B after 8 days is given as follows;

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Therefore, the number of times organism B's population is larger than organism A's population after 8 days is P₈/Pₐ = 256·a/8·a = 32 times

Which gives, the number of times organism B's population is larger than organism A's population after 8 days is 32 times.

Hope this helps you out! :)

Also, it's OK! This was actually pretty hard to figure out!

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3 years ago
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