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dimaraw [331]
3 years ago
6

Use the equation below to find v, if u=16, a=11, and t=2 V=u+at

Mathematics
1 answer:
Vinvika [58]3 years ago
3 0
The answer is 38 it would be 16+(11*2)
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What is the domain of the function shown on the graph?
blondinia [14]

Answer:

Step-by-step explanation:

Looking at the arrows on the graph, it appears that as the graph keep growing UP unbounded, it also keeps growing to the left unbounded (to negative infinity, to be exact). Looking to the right, it appears that as the graph decreases unbounded (the y values keep getting smaller), the graph keeps growing in the x direct to positive infinity. So the domain is

- ∞ < x < ∞

4 0
3 years ago
Which points on the curve of x^2 - xy - y^2 = 5 have vertical tangent lines?
algol [13]

We need to differentiate this with respect to x to see if we can find an expression for the derivative of y at various points.  That will be the slope of the tangent to the curve.  Then we want to see where that derivative might be infinite -- i.e., where the tangent is vertical.

 

It's not written as a function, but it can still be differentiated using the chain rule:

 

x2 + xy + y2 = 3

(2x) + (x dy/dx + y dx/dx) + (2y dy/dx) = 0

 

(I used parentheses to show the differentiation of each term in the original equation.)

 

2x + x dy/dx + y + 2y dy/dx = 0

2x + y = -x dy/dx - 2y dy/dx

2x + y = dy/dx (-x -2y)

-(2x + y)/(x + 2y) = dy/dx

 

We have the derivative of y, but it's defined partly in terms of y itself.  That's OK.  Let's go on...

 

So where would the slope be infinite?  That would happen when x + 2y = 0, or y = -x/2

 

Let's plug that in for y in the original equation to find points where that's the case.

 

x2 + xy + y2 = 3

x2 + x(-x/2) + (-x/2)2 = 3

x2 - x2/2 + x2/4 = 3

3x2 / 4 = 3

x2 = 4

x = ±2

 

So we have two x values where the tangent might be vertical.  Let's plug them into the equation and see what the y values are.  First x = 2...

 

x2 + xy + y2 = 3

4 + 2y + y2 = 3

y2 + 2y + 1 = 0

(y + 1)2 = 0

y = -1

 

So at the point (2, -1) the tangent is vertical.

 

Now try x = -2...

 

x2 + xy + y2 = 3

4 - 2y + y2 = 3

y2 - 2y + 1 =0

(y - 1)2 = 0

y = 1

 

So at the point (-2, 1) the tangent is vertical.

8 0
2 years ago
Brainilest to who answers first
Sauron [17]

Answer: The exponential function would be

Step-by-step explanation:

Since we have given that

We have points (0,15) and (2,24)

First we take when x= 0, y = 15.

So, our equation becomes,

and we take when x = 2 and y = 240

So, the exponential function would be

4 0
3 years ago
Marisol noticed that she does not have a common factor.
konstantin123 [22]

Answer:  option 2 describes best

Step-by-step explanation:Given Marisol grouped the terms and factored the GCF out of the groups of the polynomial 6x3 – 22x2 – 9x + 33. Her work is shown.  

Step 1: (6x3 – 22x2) – (9x + 33)

Step 2: 2x2(3x – 11) – 3(3x + 11)

Marisol noticed that she does not have a common factor. Which accurately describes what Marisol should do next?

Marisol should realize that her work shows that the polynomial is prime.

Marisol should go back and group the terms in Step 1 as (6x3 – 22x2) – (9x – 33).

Marisol should go back and group the terms in Step 1 as (6x3 – 22x2) + (9x – 33).

Marisol should refactor the expression in Step 2 as 2x2(3x + 11) – 3(3x + 11).

According to question Marisol grouped the terms and has done factorisation of the given polynomial 6x^3 – 22x^2 – 9x + 33.

In step 1 she has written as (6x^3 – 22x^2) – (9x + 33)

Marisol has to go to step 1 in order to correct her mistake. She has to group the expression as (6x^3 – 22x^2) – (9x – 33) so that she will be able to get the expression as

6x^3 – 22x^2 – 9x + 33 after opening the brackets.

4 0
3 years ago
Read 2 more answers
Find the value of x. If necessary, round your answer to the nearest tenth. The figure is not drawn to scale. (1 point) 9.7 9.2 9
Vilka [71]
X= 9.2

From the figure, the chord (12) is drawn with a line (from the center of the circle) perpendicular to it. It can be said that the chord 12 is bisected by the 7 long line from the center which gives us with 6 each of the two parts of the chord. Since they are forming (the 6 and 7) a right angled triangle, we can then use Pythagorean theorem to find X, which can be seen as the radius at the same time hypotenuse of the right angled triangle.
4 0
2 years ago
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