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3 years ago

How much string is left when 1 and 3/4 in are cut from a piece measuring 3 and 1 /6 inches

Mathematics

1 answer:

g100num [7]3 years ago

6 0

There is 1.41666... (repeating decimal) string left when 1 and 3/4 are cut from a piece measuring 3 and 1 /6 inches.

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NO LINKS!!! Find the arc measure and arc length of AB. Then find the area of the sector ABQ.

Norma-Jean [14]

Answer:

<u>Arc Measure</u>: equal to the measure of its corresponding central angle.

<u>Formulas</u>

$\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right)$

$\textsf{Area of a sector of a circle}=\left(\dfrac{\theta}{360^{\circ}}\right) \pi r^2$

$\textsf{(where r is the radius and the angle }\theta \textsf{ is measured in degrees)}$

<h3><u>Question 39</u></h3>

Given:

r = 7 in
$\theta$ = 90°

Substitute the given values into the formulas:

Arc AB = 90°

$\textsf{Arc length of AB}=2 \pi (7) \left(\dfrac{90^{\circ}}{360^{\circ}}\right)=3.5 \pi=11.00\:\sf in\:(2\:d.p.)$

$\textsf{Area of the sector AQB}=\left(\dfrac{90^{\circ}}{360^{\circ}}\right) \pi (7)^2=\dfrac{49}{4} \pi=38.48\:\sf in^2\:(2\:d.p.)$

<h3><u>Question 40</u></h3>

Given:

r = 6 ft
$\theta$ = 120°

Substitute the given values into the formulas:

Arc AB = 120°

$\textsf{Arc length of AB}=2 \pi (6) \left(\dfrac{120^{\circ}}{360^{\circ}}\right)=4\pi=12.57\:\sf ft\:(2\:d.p.)$

$\textsf{Area of the sector AQB}=\left(\dfrac{120^{\circ}}{360^{\circ}}\right) \pi (6)^2=12 \pi=37.70\:\sf ft^2\:(2\:d.p.)$

<h3><u>Question 41</u></h3>

Given:

r = 12 cm
$\theta$ = 45°

Substitute the given values into the formulas:

Arc AB = 45°

$\textsf{Arc length of AB}=2 \pi (12) \left(\dfrac{45^{\circ}}{360^{\circ}}\right)=3 \pi=9.42\:\sf cm\:(2\:d.p.)$

$\textsf{Area of the sector AQB}=\left(\dfrac{45^{\circ}}{360^{\circ}}\right) \pi (12)^2=18 \pi=56.55\:\sf cm^2\:(2\:d.p.)$

8 0

2 years ago

What is x cube + x square

MatroZZZ [7]

The answer is
x^5
is correct......

7 0

4 years ago

Aniyah spent $36 on snacks for Super Bowl Sunday and had $12 left. What percent of her money did she spend?

IgorC [24]

First, figure out how much Aniyah started with. Add. Show your work.

Then, write out the fraction (amount spent) / (amount Aniyah began with).

Last, multiply your result by 100%, and then round off the resulting percentage to the nearest integer number.

4 0

3 years ago

Heavy football players: Following are the weights, in pounds, for offensive and defensive linemen on a professional football tea

Vaselesa [24]

Answer:

a) Mean = 302.25, Median = 309.5

b) Mean = 276.08, Median = 272

c) Offensive linemen tends to be heavier.

Step-by-step explanation:

We are given the following in the question:

Offense: 325, 292, 316, 308, 325, 263, 302, 311, 265, 329, 267, 324

Defense: 265, 276, 255, 306, 317, 281, 268, 282, 260, 261, 256, 286

a) mean and median weight for the offensive linemen

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{3627}{12} = 302.25$

$Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}$

Sorted Data: 263, 265, 267, 292, 302, 308, 311, 316, 324, 325, 325, 329

$\text{Median} = \dfrac{6^{th}+7^{th}}{2}=\dfrac{308+311}{2} = 309.5$

b) mean and median weight for the defensive linemen

$Mean =\displaystyle\frac{3313}{12} = 276.08$

Sorted Data: 255, 256, 260, 261, 265, 268, 276, 281, 282, 286, 306, 317

$\text{Median} = \dfrac{6^{th}+7^{th}}{2}=\dfrac{268+276}{2} = 272$

c) Comparison

On comparing the mean and median of offensive and defensive linemen, offensive tends to be heavier

4 0

3 years ago

Use the following compound interest formula to complete the problem.

alexdok [17]

Card P's balance increased by $3.43 more than Card Q's balance. The accumulated total on Card P over the 4 years is $1080.70 and the accumulated total of Card Q is $1,206.28. Based on the principal outlay however, Card P would have netted a higher interest over Card Q when the principal is subtracted from the accumulated value. (For eg. Card P accumulated value $1080.70 less Principal $726.19 equals $354.51).The interests over the 4 years period would be $354.51 and $351.08 respectively, hence Card P having an increase in balance of $3.43 over Card Q.

5 0

4 years ago

Read 2 more answers

How much string is left when 1 and 3/4 in are cut from a piece measuring 3 and 1 /6 inches​

How much string is left when 1 and 3/4 in are cut from a piece measuring 3 and 1 /6 inches