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3 years ago

Need help finding the parallel and perpendicular slope

Mathematics

1 answer:

Rudik [331]3 years ago

8 0

Answer:

Step-by-step explanation:

(x₁, y₁) = (19 , -4) & (x₂ ,y₂) = (17, -20)

$Slope =\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$= \frac{-20-[-4]}{17-19}\\\\= \frac{-20+4}{17-19}\\\\= \frac{-16}{-2}\\\\= 8$

m = 8

Parallel lines have same slope.

Parallel slope = 8

Slope of perpendicular line = $\frac{-1}{m}$

Perpendicular slope = $\frac{-1}{8}$

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Pam has 90 m of fencing to enclose an area in a petting zoo with two dividers to separate three types of young animals. The thre

andrew-mc [135]

Answer:

The area function is

$A=\frac{135}{2}x-\frac{9}{2}x^2$ .

The domain and range of A is $(0,15m)$ and $(0, 253.125 m^2]$ .

Step-by-step explanation:

The given length of fencing is $90 m$ .

Let the length and width of each pen be $x$ and $y$ respectively as shown in the figure.

As there are 3 pens, so, the total area,

$A= 3 xy \;\cdots (i)$

From the figure the total length of fencing is $6x+4y$ .

Here, for a significant area for the animals, $x>0$ as well as $y>0$ as $x$ and $y$ are the sides of ben.

From the given value:

$6x+4y=90\;\cdots (ii)$

$\Rightarrow y=\frac {45}{2}-\frac{3x}{2}$

Now, from equation (i)

$A=3x\left(\frac {45}{2}-\frac{3x}{2}\right)$

$\Rightarrow A=\frac{135}{2}x-\frac{9}{2}x^2\;\cdots (iii)$

This is the required area function in the terms of variable $x$ .

For the domain of area function, from equation (ii)

$x=15-\frac{2y}{3}$

$\Rightarrow x$ [as y>0]

So, the domain of area function is $(0,15m)$ .

For the range of area function:

As $x \rightarrow 0$ or $y\rightarrow 0$ , then $A\rightarrow 0$ [from equation (i)]

$\Rightarrow A>0$

Now, differentiate the area function with respect to $x$ .

$\frac {dA}{dx}=\frac{135}{2}-9x$

Equate $\frac {dA}{dx}$ to zero to get the extremum point.

$\frac {dA}{dx}=0$

$\Rightarrow \frac{135}{2}-9x=0$

$\Rightarrow x=\frac{15}{2}$

Check this point by double differentiation

$\frac {d^2A}{dx^2}=-9$

As, $\frac {d^2A}{dx^2}$ , so, point $x=\frac{15}{2}$ is corresponding to maxima.

Put this value back to equation (iii) to get the maximum value of area function. We have

$A=\frac{135}{2}\times \frac {15}{2}-\frac{9}{2}\times \left(\frac {15}{2}\right)^2$

$\Rightarrow A=253.125 m^2$

Hence, the range of area function is $(0, 253.125 m^2]$ .

4 0

4 years ago

Y=-x+8 what is this can you tell me

GREYUIT [131]

Answer:

algebra

Step-by-step explanation:- x - 8.

brainliest plzzz

4 0

3 years ago

Read 2 more answers

HALP PLEASE DO 6 AND 7 PLEASEEE

Harman [31]

Answer:

Step-by-step explanation:

6) Convert mixed fraction to improper fraction and then plugin the values in the formula.

$l= 3\frac{1}{3} yard=\frac{10}{3}\\\\w = 1\frac{5}{9} yard=\frac{14}{9}\\\\h =2\frac{1}{4} yard=\frac{9}{4}\\\\Volume of wood shed = l * w *h\\\\= \frac{10}{3}*\frac{14}{9}*\frac{9}{4}\\\\= \frac{5}{3}*\frac{7}{1}*\frac{1}{1}\\\\=\frac{5*7}{3}\\\\=\frac{35}{3}\\\\=11\frac{2}{3} cubic yard$

b) 10 cubic yard is less than 11 2/3 cubic yard. So, it will fit in the wood shed.

7) Right side rectangular prism:

l = 16 in

w = 5 in

h = 20 - 14 = 6 in

Volume 1 = 16 * 5 * 6 = 480 cubic inches

Left side rectangular prism:

l = 9 in

w = 5 in

h =14 in

Volume 2 = 9 * 5 * 14 = 630 cubic in

Volume of composite solid = 480 + 630 = 1110 cubic inches

7 0

3 years ago

What are the factors of the expression (y-2)(x+3)

ivanzaharov [21]

(y-x) (2+3)= (yx)(5)
But am not sure it could be =(2-3) (y+x) = (1) (yx)

5 0

4 years ago

Read 2 more answers

A probability distribution is a listing of all the outcomes of an experiment and the probability associated with each outcome. T

Novosadov [1.4K]

Answer:

True.

Step-by-step explanation:

A probability distribution is a listing of all the outcomes of an experiment and the probability associated with each outcome. Probability distribution is associated with the following characteristics or properties;

1. The outcomes are mutually exclusive.

2. The list of outcomes is exhaustive, which simply means that the sum of all probabilities of the outcomes must equal one (1).

3. The probability for a particular value or outcome must be between 0 and 1.

Since a probability distribution gives the likelihood of an outcome or event, a single random variable is divided into two main categories, namely;

I. Probability density functions for continuous variables.

II. Discrete probability distributions for discrete variables.

For example, when a coin is tossed, you can only have a head or tail (H or T).

Also, when you throw a die, the only possible outcome is 1/6 and the total probability for it all must equal to one (1).

5 0

3 years ago