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olganol [36]
3 years ago
10

To start a road trip, a car encountered a traffic jam, traveling a total of m miles after the first hour and a total of m2 miles

after the second hour. If the ratio of the distance traveled during the first hour to the distance traveled during the second hour is 1 to 7, how far had the car traveled after 2 hours?
Mathematics
1 answer:
Monica [59]3 years ago
5 0
56 miles, The car traveled m miles during the first hour and m squared miles during the second hour. The ratio m/m squared = 1/7 and cross multiplying yields m squared = 7m, so m=7. This means that the total distance traveled was 7+7squared = 56 miles
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Simplify the expression<br> (-3+4k) - (-2+ 7k)
DedPeter [7]

Answer: −1−3k

Step-by-step explanation:

Distribute:

(−3+4k)−1(−2+7k)

(-3+4k)+{2-7k}

Eliminate redundant parentheses:

(−3+4k)+2−7k

-3+4k+2-7k

Add the numbers:

−3+4k+2−7k

−1+4k−7k

Add the same term to both sides of the equation:

−1+4k−7k

−1−3k

4 0
3 years ago
Whats the correct answer answer asap
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5 0
2 years ago
Is 3/8 bigger than 45/100
marusya05 [52]
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5 0
3 years ago
Need help with this please
Crazy boy [7]

Answer:

1. 2(k + 3)

2. 3. 75 + k

Step-by-step explanation:

1. 2x + 6

Since, 2 is a common factor of 2 and 6, we can take that common outside.

So, 2x + 6 = 2(x + 3)

Note that in the initial expression, this 2 was distributed to arrive at 2x + 6.

2. (1.5 + k) + 2.25

This is simple addition. We can simply remove the brackets to have:

1.5 + k + 2.25

Since, the like terms can be added, we will have:

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8 0
3 years ago
The amounts a soft drink machine is designed to dispense for each drink are normally distributed, with a mean of 12.1 fluid ounc
Ludmilka [50]

Answer:

\mu = 12.1\\\sigma = 0.3

a) Find the probability that the drink is less than 11.9 fluid ounces

We are supposed to find P(x<11.9)

x= 11.9

We will use z score formula :

z=\frac{x-\mu}{\sigma}

z=\frac{11.9-12.1}{0.3}

z=-0.67

Refer the z table

So, P(z<-0.67) = 0.2514

Hence the probability that the drink is less than 11.9 fluid ounces is 0.2514

b)Find the probability that the drink is between 11.6 and 11.9 fluid ounces

x= 11.6

We will use z score formula :

z=\frac{x-\mu}{\sigma}

z=\frac{11.6-12.1}{0.3}

z=-1.67

x= 11.9

We will use z score formula :

z=\frac{x-\mu}{\sigma}

z=\frac{11.9-12.1}{0.3}

z=-0.67

We are supposed to find P(11.6<x<11.9)

So, P(11.6<x<11.9)= P(x<11.9)-P(x<11.6)

P(-1.67<z<-0.67)= P(z<-0.67)-P(z<-1.67)

Refer the z table

P(-1.67<z<-0.67)= P(z<-0.67)-P(z<-1.67)

P(-1.67<z<-0.67)= 0.2514-0.0475

P(-1.67<z<-0.67)= 0.2039

So, the probability that the drink is between 11.6 and 11.9 fluid ounces is 0.2039.

c)Find the probability that the drink is more than 12.6 fluid ounces

We are supposed to find P(x>12.6)

x= 12.6

We will use z score formula :

z=\frac{x-\mu}{\sigma}

z=\frac{12.6-12.1}{0.3}

z=1.67

Refer the z table

P(x>12.6)=1-P(x<12.6)

P(z>1.67)=1-P(z<1.67)

P(z>1.67)=1-0.9525

P(z>1.67)=0.0475

Hence  the probability that the drink is more than 12.6 fluid ounces is 0.0475

d) Is the drink containing more than 12.6 fluid ounces an unusual event?

Since p value is less than  alpha (0.05)

Answer = No, because the probability that a drink containing more than 12.6 fluid ounces is less than 0.05, this event is not unusual.

3 0
3 years ago
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