What inequality is on the number line?
2 answers:
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The correct choice of this question with the given polynomial is <em>"The zeros are </em>-2<em> and </em>8<em>, because the factors of g are (x + </em>2<em>) and (x - </em>8<em>)"</em>. (Correct choice: H)
<h3>How to analyze a second orden polynomial with constant coefficients</h3>
In this case we have a second order polynomial of the form <em>x² - (r₁ + r₂) · x + r₁ · r₂</em>, whose solution is <em>(x - r₁) · (x - r₂)</em> and where <em>r₁</em> and <em>r₂</em> are the roots of the polynomial, which can be real or complex numbers but never both according the fundamental theorem of algebra.
If we know that <em>g(x) =</em> <em>x² -</em> 6 <em>· x -</em> 16, then the <em>factored</em> form of the expression is <em>g(x) = (x - </em>8<em>) · (x + </em>2<em>)</em>. Hence, the correct choice of this question with the given polynomial is <em>"The zeros are </em>-2<em> and </em>8<em>, because the factors of g are (x + </em>2<em>) and (x - </em>8<em>)"</em>.
To learn more on polynomials, we kindly invite to check this verified question: brainly.com/question/11536910
Answer:
helloo…
Step-by-step explanation:
I probably solved it right…
(If you don't understand my writing, I will rewrite it)
Notice the picture,
recall your SOH, CAH, TOA
you have,
opposite side, 165
adjacent side, 50
and the angle
that means, we'll need Mrs. tangent
thus
![\bf tan(\theta)=\cfrac{opposite}{adjacent}\implies tan(\theta)=\cfrac{165}{50} \\ \quad \\ tan^{-1}\left[ tan(\theta) \right]=tan^{-1}\left[ \cfrac{165}{50} \right] \\ \quad \\ \theta=tan^{-1}\left[ \cfrac{165}{50}\right] \\ \uparrow \\ \textit{angle of elevation}\iff\textit{angle of depression}](https://tex.z-dn.net/?f=%5Cbf%20tan%28%5Ctheta%29%3D%5Ccfrac%7Bopposite%7D%7Badjacent%7D%5Cimplies%20tan%28%5Ctheta%29%3D%5Ccfrac%7B165%7D%7B50%7D%0A%5C%5C%20%5Cquad%20%5C%5C%0A%20tan%5E%7B-1%7D%5Cleft%5B%20tan%28%5Ctheta%29%20%5Cright%5D%3Dtan%5E%7B-1%7D%5Cleft%5B%20%5Ccfrac%7B165%7D%7B50%7D%20%5Cright%5D%0A%5C%5C%20%5Cquad%20%5C%5C%0A%5Ctheta%3Dtan%5E%7B-1%7D%5Cleft%5B%20%5Ccfrac%7B165%7D%7B50%7D%5Cright%5D%0A%5C%5C%20%5Cuparrow%20%20%5C%5C%0A%20%5Ctextit%7Bangle%20of%20elevation%7D%5Ciff%5Ctextit%7Bangle%20of%20depression%7D)
recall your SOH, CAH, TOA
you have,
opposite side, 165
adjacent side, 50
and the angle
that means, we'll need Mrs. tangent
thus