The value of x in x^yz = y^2 is ![x = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
<h3>How to solve for x?</h3>
The equation is given as:
x^yz = y^2
Rewrite the equation properly as follows

Take the yz root of both sides
![\sqrt[yz]{x^{yz}} = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=%5Csqrt%5Byz%5D%7Bx%5E%7Byz%7D%7D%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
Apply the law of indices
![x^{\frac{yz}{yz}} = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7Byz%7D%7Byz%7D%7D%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
Divide yz by yz
![x = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
Hence, the value of x in x^yz = y^2 is ![x = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
Read more about equations at:
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Answer:
68469.44
Multiplication is commutative so can be multiplied anyway
(2.0× 109)(3.02×104)
2.0 can be written as ( 20÷ 10) and 3.02 can be written as (302÷ 100)
(2× 109){(3.02÷ 100)× 104]
(218)(7852÷ 25)
68469.44
Plug in the values of the ordered pairs into the equations.
41 = 5(8) + 1
41 = 40 + 1
41 = 41
So, A y = 5x + 1 is the answer.
Answer is 47.
- a prime number only has factors of one and itself
- other numbers were composite
- 45 can be divided by 5
- 46 can be divided by 2
- 48 can be divided by 2
- 49 is 7^2
Answer:
x = 125°
Step-by-step explanation:
The sum of the angles around a point = 360° , then
90 + 145 + x = 360°
235° + x = 360° ( subtract 235° from both sides )
x = 125°