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Ganezh [65]
3 years ago
14

The Calculate the perimeter of Following Shape: 8cm 5cm

Mathematics
2 answers:
mina [271]3 years ago
7 0

Answer:

where is your shape

Step-by-step explanation:

firstly give shape then we find out perimeter

na

Gekata [30.6K]3 years ago
3 0

Answer:

26cm

Step-by-step explanation:

Assuming it has 2 sides 8 cm and 2 sides 5cm then

8 + 8 = 16

5 + 5 = 10

16 + 10 = 26

hopefully this helps!

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On a scale drawing, a building is 5.5 tall. If the scale if the drawing is 1 inch: 8 ft, how tall is the building
arsen [322]
First, since the building is 5.5 inches and the scale is 1 inch for 8 feet, you would multiply 5.5* 8 to get 44 feet.
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You have just bought 4 bottles of water containing 750 ml each. How many litres of water do you have in total?
gulaghasi [49]
You have 187.5 because you divide 750 by 4



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Pls show work! questions on pic
Lena [83]

Answer:

a.(10,23)

b.(7,30)

e.(20,20)

Step-by-step explanation:

We are given that

x=Width of garden

y=Length of garden

According to question

x\geq 5

y\geq 20

Perimeter of rectangle=2(x+y)

Where x=Width  of rectangle

y=Length of rectangle

Fencing used =2(x+y)

2(x+y)\leq 80

First we change inequality  into equality

x=5...(1)

y=20...(2)

2(x+y)=80

x+y=40...(3)

Substitute x=0 in equation (3)

y=40

Substitute y=0  in equation (3)

x=40

Substitute x=0 and y=0 in equation (3)

2(x+y)\leq 80

0\leq 80

It is true. Therefore, the  shaded region below the line.

0\geq 5

0\geq 20

These are false equation .Therefore, the shaded region above the line.

Substitute x=5 in equation (3)

5+y=40

y=40-5=35

Substitute y=20 in equation (3)

x+20=40

x=40-20=20

Intersection point of equation (1) and (3) is (5,35) and intersect point of equation (2) and (3) is (20,20).

Now,

a.(10,23)

Substitute in

2(x+y)\leq 80

2(10+23)\leq 80

66\geq 80

10>5 and 23>20

it satisfied all inequality.

Hence, it is a solution.

b.(7,30)

7>5

30>20

2(7+30)=74

it satisfied all inequality.

Hence, it is a solution.

c.(18,25)

18>5

25>20

2(18+25)=86>80

It does not satisfied third inequality

Hence, it is not a solution.

d.(8,35)

8>5

35>20

2(8+35)=86>80

It does not satisfied third inequality

Hence, it is not a solution.

e.(20,20)

2(20+20)=80

20>5

20=20

it satisfied all inequality.

Hence, it is a solution.

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