Shampoo can be bought in 5 gallon pails. The groomer uses 16 ounce bottles to to hold the shampoo. How many bottles can he get o
1 answer:
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Answer:
The radius of the inflated spherical balloon is 45 millimeters.
Step-by-step explanation:
Volume of the spherical water balloon = 121,500 pi cubic millimeters
Let the radius of the balloon = r
Now, Volume of a Sphere =
⇒
On solving for the value of r, we get:
or, r = 45 millimeter
Hence, the radius of the inflated spherical balloon is 45 millimeters.
Answer:
Options (1), (5), and (6)
Step-by-step explanation:
See attached image
The sketch of the garden and the pond is shown below
Area of garden = length × width
Area of garden = [3x + 5] × 3x
Area of garden = 3x[3x+5]
Area of garden = 9x² + 15x
Area of pond = [x-2] × x
Area of pond = x[x-2]
Area of pond = x² - 2x
Area to be re-sod = Area of garden - Area of pond
Area to be re-sod = 9x² + 15x - [x² - 2x]
Area to be re-sod = 9x² - x² + 15x + 2x
Area to be re-sod = 8x² + 17x
The amount of sod needed to be bought would depend on how much in each packaging they are being sold.
Area of garden = length × width
Area of garden = [3x + 5] × 3x
Area of garden = 3x[3x+5]
Area of garden = 9x² + 15x
Area of pond = [x-2] × x
Area of pond = x[x-2]
Area of pond = x² - 2x
Area to be re-sod = Area of garden - Area of pond
Area to be re-sod = 9x² + 15x - [x² - 2x]
Area to be re-sod = 9x² - x² + 15x + 2x
Area to be re-sod = 8x² + 17x
The amount of sod needed to be bought would depend on how much in each packaging they are being sold.