Answer:
a. x = 2 , x = -5
b. no real roots
Step-by-step explanation:
<u>a. x² + 3x – 10</u>
= x² - 2x + 5x - 10
= x (x²/x - 2x/x) + 5 (5x/5 - 2*5/5)
= (x - 2) (x + 5)
x - 2 = 0 x + 5 = 0
+ 2 +2 -5 -5
-------------- ---------------
x = 2 x = -5
x = 2 , x = -5
<u>b. 2x² - 4x + 3 </u>
This can't be solved because the equation has no real roots, and also the discriminant is negative.
Um this seems really confusing!
Answer:
The y-intercept is (0, 3)
<em>they typed the equation wrong so that's why it's (0, 3)</em>
A variable represents an unknown number
Answer:
Angle Q is 51°
Angle R is 96°
(x=5 and the exterior angle is 84°)
Step-by-step explanation:
Exterior Angle Theorem says that angle that's outside the triangle (extend a side and see the angle between the side extension and the side) IS Equal to the sum of the two angles that are farther away.
17x - 1 = 33 + 10x + 1
Get all the x's on one side of the equation.
17x-10x - 1 = 33 + 10x-10x+1
7x - 1 = 33 + 1
7x - 1 = 34 add 1 to both sides
7x = 35 divide by 7
7x/7 = 35/7
x = 5
Not finished ! Find Angle Q
10x+1 = 10(5)+1= 51°
Angle PRQ is insidethe triangle. All the angles of a triangle add up to 180°
33° + 51° + R = 180°
84° + R = 180°
R = 96°
