Solve the following equation for D: fD-7=q2
1 answer:
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Answer:
99% CI: [45.60; 58.00]min
Step-by-step explanation:
Hello!
Your study variable is:
X: Time a customer stays in a certain restaurant. (min)
X~N(μ; σ²)
The population standard distribution is σ= 17 min
Sample n= 50
Sample mean X[bar]= 51.8 min
Sample standard deviation S= 27.68
You are asked to construct a 99% Confidence Interval. Since the variable has a normal distribution and the population variance is known, the statistic to use is the standard normal Z. The formula to construct the interval is:
X[bar] ± *(σ/√n)
Upper level: 51.8 - 2.58*(17/√50) = 45.5972 ≅ 45.60 min
Lower level: 51.8 + 2.58*(17/√50) = 58.0027 ≅58.00 min
With a confidence level of 99%, you'd expect that the interval [45.60; 58.00]min will contain the true value of the average time customers spend in a certain restaurant.
I hope you have a SUPER day!
PS: Missing Data in the attached files.
Answer:
(3, 0 )
Step-by-step explanation:
Given a parabola in standard form
y = ax² + bx + c (a ≠ 0 )
Then the x- coordinate of the vertex is
= -
y = 5x² - 30x + 45 ← is in standard form
with a = 5, b = - 30 , then
= -
= 3
Substitute x = 3 into the function for corresponding value of y
y = 5(3)² - 30(3) + 45 = 45 - 90 + 45 = 0
vertex = (3, 0 )