The cheerleader section is on the basketball court. Each row requires a section of floor that is 1 ¾ yards by 3 ⅓ yards. How man
1 answer:
Answer:
The area of the floor space is equal to 5.83 sq yards.
Step-by-step explanation:
Given that,
Each row requires a section of floor that is 1 ¾ yards by 3 ⅓ yards.
We need to find how many square yards of floor space are taken up by one row of cheerleaders.
We know that, the area of a rectangle is given by :
A = lb
So,
So, the area of the floor space is equal to 5.83 sq yards.
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We are given the equations 3x+5y=-3 and x-5y=-5.
Both equations have a 5y term which allows us to easily solve the system by elimination. To do so we will add the equations together like a simple addition problem by adding the x terms together, the y terms together, and the integer answers together.
3x + 5y = -3
+x - 5y = -5
---------------
4x + 0y = -8
The y terms cancel out since one is positive and one is negative. Now we can solve for x.
4x = -8
x = -2
Now plug -2 in for x in one of the original equations to find y.
(-2) - 5y = -5
-5y = -3
y = 3/5
Our answer as an ordered pair is (2, 3/5)
Both equations have a 5y term which allows us to easily solve the system by elimination. To do so we will add the equations together like a simple addition problem by adding the x terms together, the y terms together, and the integer answers together.
3x + 5y = -3
+x - 5y = -5
---------------
4x + 0y = -8
The y terms cancel out since one is positive and one is negative. Now we can solve for x.
4x = -8
x = -2
Now plug -2 in for x in one of the original equations to find y.
(-2) - 5y = -5
-5y = -3
y = 3/5
Our answer as an ordered pair is (2, 3/5)
Assuming that we are performing a two-tailed test, the significance level is α = 0.1 would be dispersed in the distribution's tails with α/2 = 0.05.
And we must consider two critical values that add up to 0.05 of a area on every tail of a F distribution with a 10 degree angle.
An F statistic is one that is ascertained through an ANOVA test. It helps determine the relevance of the variable groups.
Now, according to the question;
We understand that sample size for numerator is 11 and also the sample size for denominator is 7. So, for each case, we can calculate a degrees of freedom as follows:
In this case, the F distribution could have 10 degrees of freedom with in numerator as well as 6 degrees of freedom in the denominator.
Assuming we are conducting a two-tailed test, the significance level of α = 0.1 will be distributed in the tails of the distribution with α/2 = 0.05.
Now, locate two critical values that collect 0.05 of a area on every tail of F distribution to 10 degrees of freedom again for numerator and 6 degrees of freedom for the denominator and we obtained using a table or excel;
Therefore, the critical f-value for the two-tailed experiment is found.
To know more about the critical f-value, here
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