2 years ago

PLEASE HELPPPP Prove That: 5^31–52^9 is divisible by 100. do it like _____*100

Mathematics

1 answer:

Andru [333]2 years ago

8 0

Answer:

5^31

Step-by-step explanation:

10052^9

This should be correct

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The fraction of defective integrated circuits produced in a photolithography process is being studied. A random sample of 300 ci

4vir4ik [10]

Answer:

(a) The confidence interval is: 0.0304 ≤ π ≤ 0.0830.

(b) Upper confidence bound = 0.0787

Step-by-step explanation:

(a) The confidence interval for p (proportion) can be calculated as

$p \pm z*\sigma_{p}$

$\sigma=\sqrt{\frac{\pi*(1-\pi)}{N} }\approx\sqrt{\frac{p(1-p)}{N} }$

NOTE: π is the proportion ot the population, but it is unknown. It can be estimated as p.

$p=17/300=0.0567\\\\\sigma=\sqrt{\frac{p(1-p)}{N} }=\sqrt{\frac{0.0567(1-0.0567)}{300} }=0.0134$

For a 95% two-sided confidence interval, z=±1.96, so

$\\LL = p-z*\sigma=0.0567 - (1.96)(0.0134) = 0.0304\\UL =p+z*\sigma= 0.0567 + (1.96)(0.0134) = 0.0830\\\\$

The confidence interval is: 0.0304 ≤ π ≤ 0.0830.

(b) The confidence interval now has only an upper limit, so z is now 1.64.

$UL =p+z*\sigma= 0.0567 + (1.64)(0.0134) = 0.0787$

The confidence interval is: -∞ ≤ π ≤ 0.0787.

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Find the volume of the following cone. Use 3.14 for n and

fenix001 [56]

28 m because it is the smallest number

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otez555 [7]

In decimal form it is 1.8

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Mandarinka [93]

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Sliva [168]

Answer:

1/2pi

Step-by-step explanation:

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