The fraction of the numbers in the distribution that are between 50 and 70 is; 95/100
<h3>How to use the empirical rule in statistics?</h3>
We are given;
Mean = 60
Standard deviation = 5
To find the numbers in the distribution that are between 50 and 70, it means that the numbers are going to be 2 standard deviations from the mean because 2σ = 2 * 5 = 10 which is the difference of both pairs from the mean.
According to empirical rule, 2 standard deviations from the mean is approximately 95/100 or 95%.
Complete question is;
In a certain distribution, the mean is 60 with a standard deviation of 2. At least what traction of the numbers are between the following pair of numbers? At least of the numbers in the distribution are between 50 and 70
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Answer:
(1-cosA)/(1+cosA)
=(1-cosA)/(1+cosA) ×(1-cosA)/(1-cosA)
=(1-cosA)^2 /(1-cos^2A)
=(1-cosA)^2 / (sin^2A)
=(1/sinA - cosA/sinA )^2
=cosecA - cotA)^2
Hope it helps
Have a great Day ; )
Answer:
See below
Step-by-step explanation:
a)
<u>Day 1</u>
- 70 min for 10 km
- Rate = 70/10 = 7 min/km
<u>Day 10</u>
- 2h40 min for 20 km
- 2*60+40 = 160 min for 20 km
- Rate = 160/20 = 8 min/km
<u>Day 20</u>
- 4 h 15 min for 30 km
- 4*60 + 15 = 255 min for 30 km
- Rate = 255/30 = 8.5 min / km
b)
<u>From the rate change we see:</u>
- 1 min increase when the distance increases from 10 km to 20 km
- 0.5 min increase when distance increases from 20 km to 30 km
So we see 1 min increase per twice the distance increase
- With the same rate increase we can expect 1 min increase from 20 km to 40 km, which gives us the rate of 9 min/km
- With same logic we get 9.055 km/min rate for 44 km distance
<u>Total time it takes:</u>
- 9.055*44 = 398.42 min = 398.42*1/60 min = 6 h and 38.42 min