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docker41 [41]
3 years ago
13

A total of 500 married working couples were polled about their annual salaries, with the following information resulting: Husban

d Wife Less than More than $25,000 $25,000 Less than $25,000 212 198 More than $25,000 36 54 For instance, in 36 of the couples, the wife earned more and the husband earned less than $25,000. If one of the couples is randomly chosen, what is (a) the probability that the husband earns less than $25,000
Mathematics
1 answer:
Dimas [21]3 years ago
7 0

Answer:

36/500

Step-by-step explanation:

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Please help me guys this is due in 5 mins!
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Answer:

Fraction: 1/2

Decimal: 0.5

Percent: 50%

Step-by-step explanation:

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According to the National Bridge Inspection Standard (NBIS), public bridges over 20 feet in length must be inspected and rated e
slamgirl [31]

Answer:

1.80% probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Step-by-step explanation:

For each bridge, there are only two possible outcomes. Either it has rating of 4 or below, or it does not. The probability of a bridge being rated 4 or below is independent from other bridges. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

For the year 2020, the engineers forecast that 9% of all major Denver bridges will have ratings of 4 or below.

This means that p = 0.09

Use the forecast to find the probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Either less than 4 have a rating of 4 or below, or at least 4 does. The sum of the probabilities of these events is 1.

So

P(X < 4) + P(X \geq 4) = 1

We want P(X \geq 4)

So

P(X \geq 4) = 1 - P(X < 4)

In which

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{12,0}.(0.09)^{0}.(0.91)^{12} = 0.3225

P(X = 1) = C_{12,1}.(0.09)^{1}.(0.91)^{11} = 0.3827

P(X = 2) = C_{12,2}.(0.09)^{2}.(0.91)^{10} = 0.2082

P(X = 3) = C_{12,3}.(0.09)^{3}.(0.91)^{9} = 0.0686

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.3225 + 0.3827 + 0.2082 + 0.0686 = 0.982

Finally

P(X \geq 4) = 1 - P(X < 4) = 1 - 0.982 = 0.0180

1.80% probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

6 0
3 years ago
I asked this earlier and got no answer. Will give brainliest
Virty [35]
The area of a square is

s • s

We can also write this as

s^2

So, for any side length “s”, we can make a function, A(s), such that

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Now that we have a quadratic equation for the area of a square, let’s go ahead and solve for the side lengths of a square with a given area. In this case, 225 in^2

225 = s^2

Therefore,

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3 years ago
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Answer:

$15

Step-by-step explanation:

Given that :

Aunt's distance = 120 miles

Miles per gallon of Olivia's car = 24 miles per gallon

Cost of gasoline = 3 per gallon

Cost of gasoline for the trip :

(Aunt's distance / miles per gallon) * cost of gasoline per gallon

(120 miles / 24 miles per gallon) * 3

5 * 3 = $15

Cost of gasoline for the trip = $15

8 0
2 years ago
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