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Ghella [55]
2 years ago
5

The third term in an arithmetic sequence is 9 and the fifth term is 21 . If the first term if a1, which is an equation for the n

th term of this sequence?
A:an=6n-9
B:an=14n+6
C:an=6n+14
D:an=9n-6
Mathematics
1 answer:
tino4ka555 [31]2 years ago
3 0

Answer:

A: an = 6n - 9

Step-by-step explanation:

third term in an arithmetic sequence is 9

a3 = a + 2d

a + 2d = 9

the fifth term is 21

a5 = a + 4d

a + 4d = 21

a + 2d = 9 (1)

a + 4d = 21 (2)

Subtract (1) from (2) to eliminate a

4d - 2d = 21 - 9

2d = 12

d = 12/2

d = 6

Substitute d = 6 into (1)

a + 2d = 9 (1)

a + 2(6) = 9

a + 12 = 9

a = 9 - 12

a = -3

nth term of this sequence = a + (n - 1)d

= -3 + (n - 1)6

= -3 + 6n - 6

= 6n - 9

an = 6n - 9

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Gnom [1K]

4x² - 16 is the algebraic expression that must be added to get the result as 9x²- 2x - 5.

<u>Step-by-step explanation:</u>

The question is asked for the algebraic expression must be added to the sum of 3x²+4x+8 and 2x2−6x+3 to give 9x²- 2x - 5 as the result.

Therefore,

The first step is to find of sum of 3x²+4x+8 and 2x²-6x+3.

To find the sum :

3x²+4x+8

<u>2x²-6x+3 </u>

<u>5x²-2x+11</u>

The sum is 5x²-2x+11.

Now, the second step is to subtract 5x²-2x+11 from the result 9x²- 2x - 5.

  9x²- 2x - 5

- <u>(5x²-2x+11)</u>

  <u> 4x²    -16 </u>

Thus, 4x²-16 is the algebraic expression that must be added with 5x²-2x+11 to get a result of 9x²- 2x - 5.

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3 years ago
Mrs. Bogaczyk got bored and decided to go on an Amazon spending spree! She bought 3 pairs of flip flops for $14.95 each, a sundr
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Mrs B spent 99.12 altogether

Budget = 100

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Base your answer on Betty is thinking of two consecutive integers whose sum is 41.
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Answer:

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so, x + ( x + 1 ) = 41

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6 0
3 years ago
If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by
Vitek1552 [10]

Answer:

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by y = 70t-16t^2.

To find : The average velocity for the time period beginning when t = 2 and lasting.  a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :    

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}

(\text{Average velocity})_{0.1\ s}=696\ ft/s

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}

(\text{Average velocity})_{0.01\ s}=7536\ ft/s

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

(\text{Average velocity})_{0.001\ s}=\frac{\text{Change in height}}{0.001}  

(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}

(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}

(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}

(\text{Average velocity})_{0.001\ s}=75936\ ft/s

5 0
3 years ago
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