The answer is D.
First, separate the compound equality into 2
1st -3 (x-4) greater than/ equal to 21
2nd -3( x-4) < 30
Second, solve the inequality for x
1st x less than/ equal to -3
2nd x > -6
Third, find the intersection
D. -6 < x (less than/equal) to -3
I hope this helped, and if you don’t mind, giving me brainiest!
Probaility is (desired outcomes)/(total possible outcomes)
odd numbers of dice is 3 (1,3,5)
desired outcomes =3
dice has 6 numbers
total possible outcomes of diece=6
3/6=1/2=dice
coin
tails=1
desired outcomes=1
total possibe=2 since 2 sides (head and tails)
cond poinbabiotiuyy=1/2
they are independend of each other since they do not influence each other
if they were like 'pick 2 collor balls and see what color you get, when you pick one, there is 1 less ball int he bucket so the propbabilit changes'
so
assuming that
P(M and N)= means
'the probability of M and N are both equal to "
The two events are independent. In the given scenario, P(M and N) =1/2.
It is A.. Value of log2^100 is about 4 times the value of log6^20
Answer:
Attached below
Step-by-step explanation:
sorry couldnt d it on paper ;)
