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artcher [175]
3 years ago
11

Does anyone know the answer to this question.....0.5x + 1.75 = 10

Mathematics
1 answer:
marysya [2.9K]3 years ago
3 0

Answer:

x = 16.5

Step-by-step explanation:

0.5x + 1.75 = 10

Subtract 1.75 from both sides:

0.5x = 8.25

Divide both sides by 0.5

x = 16.5

Check your work!

0.5(16.5) + 1.75 = 10

8.25 + 1.75 = 10

10 = 10

x = 16.5

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1/2 s + 3/4 s + 1/4 s + 4

((2+3+1)/4)s +4

6/4 s + 4

3/2 s + 4

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Check the picture below.

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4 years ago
In an engineering test, a rocket sled is propelled into a target. The sled’s distance d in meters from the target is given by th
creativ13 [48]
You're given d = 10
10 = -1.5t<span>2 = 110
</span>t^{2} = 220/3
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6 0
3 years ago
S
Novay_Z [31]

Step-by-step explanation:

s is inversely proportional to t

If s= 0.6 , t= 4

s=k/t

0.6= k/4

k=2.4

If s=12, then

t=k/s

t=2.4/12

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8 0
2 years ago
Find the x- and y- intercepts of parabola y=5x^2-16x+10
____ [38]

Y-INTERCEPT

y = 5x^2 - 16x + 10

The y-intercept is where the equation/curve/parabola cosses the y-axis.

The y-axis is where x = 0. (The x-axis is where y = 0)

To find the y-intercept:

\text{y-axis} \rightarrow \text{x = 0} \rightarrow y = 5(0)^2 -16(0) + 10 = 10

The y-intercept must be at (0, 10)

X-INTERCEPT (ROOTS/SOLUTIONS)

y = 5x^2 - 16x + 10\\\text{make it equal 0}\\y = 0\\\therefore 5x^2 - 16x + 10 = 0

We need to use the quadratic formula

The quadratic formula helps us find what values of x make the equation = 0

Quadratic formula: x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-(-16) + \sqrt{(-16)^2-4(5)(10)}}{2(5)}\\\\x = \frac{16 + \sqrt{256-200}}{10}\\x = \frac{16 + \sqrt{56}}{10}\\x = \frac{16 + 2\sqrt{14}}{10}\\x = \frac{8 + \sqrt{14}}{5}\\\\\\x=\frac{-(-16) - \sqrt{(-16)^2-4(5)(10)}}{2(5)}\\\text{doing the same thing...}\\\text{end up with...}\\x = \frac{8 - \sqrt{14}}{5}\\

The x-intercepts are at:

(\frac{8 + \sqrt{14}}{5}, 0)\\(\frac{8 - \sqrt{14}}{5}, 0)

5 0
2 years ago
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