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3 years ago

What is the value of the expression below when x=3

Mathematics

1 answer:

Ad libitum [116K]3 years ago

4 0

Answer:

There is no image

Step-by-step explanation:

Try isolating the variable in the equation

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how do you write y - 2 = -(x - 3) in slope-intercept form? A) y = x + 3 B) y = x - 1 C) y = -x + 5 D) y = -3x - 1

SashulF [63]

C) y= -x+5
explain:
y-2=-x+3
y= -x+3+2
so y= -x+5

5 0

2 years ago

Use Lagrange multipliers to find the maximum and minimum values of f(x,y)=x+4y subject to the constraint x2+y2=9, if such values

Vesnalui [34]

The Lagrangian is

$L(x,y,\lambda)=x+4y+\lambda(x^2+y^2-9)$

with critical points where the partial derivatives vanish.

$L_x=1+2\lambda x=0\implies x=-\dfrac1{2\lambda}$

$L_y=4+2\lambda y=0\implies y=-\dfrac2\lambda$

$L_\lambda=x^2+y^2-9=0$

Substitute $x,y$ into the last equation and solve for $\lambda$ :

$\left(-\dfrac1{2\lambda}\right)^2+\left(-\dfrac2\lambda\right)^2=9\implies\lambda=\pm\dfrac{\sqrt{17}}6$

Then we get two critical points,

$(x,y)=\left(-\dfrac3{\sqrt{17}},-\dfrac{12}{\sqrt{17}}\right)\text{ and }(x,y)=\left(\dfrac3{\sqrt{17}},\dfrac{12}{\sqrt{17}}\right)$

We get an absolute maximum of $3\sqrt{17}\approx12.369$ at the second point, and an absolute minimum of $-3\sqrt{17}\approx-12.369$ at the first point.

4 0

2 years ago

How old is a dog when they are 40 in human years?

Scorpion4ik [409]

Answer:

280 years old

Step-by-step explanation:

to determine a dog's age in dog or human years, you divide or multiply by 7

40x7=280 years

4 0

3 years ago

on the first day of the year, you have $700 in your bank account. you spend $35 per week. your friend starts the year with $450

____ [38]

5weeks
Good! Since you want to find when both of you have the same amount of money, you can set the two expressions representing the money equal to each other. This gives the equation $700 – $35 per week • weeks = $450 + $15 per week • weeks. Solving the equation, you find that you will have the same amount of money in 5 weeks.

7 0

3 years ago

Read 2 more answers

Items produced by a manufacturing process are supposed to weigh 90 grams. The manufacturing procon

Annette [7]

Using the normal distribution, it is found that 0.26% of the items will either weigh less than 87 grams or more than 93 grams.

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

The mean is of 90 grams, hence $\mu = 90$ .

The standard deviation is of 1 gram, hence $\sigma = 1$ .

We want to find the probability of an item differing more than 3 grams from the mean, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{3}{1}$

$Z = 3$

The probability is P(|Z| > 3), which is 2 multiplied by the p-value of Z = -3.

Looking at the z-table, Z = -3 has a p-value of 0.0013.

2 x 0.0013 = 0.0026

0.0026 x 100% = 0.26%

0.26% of the items will either weigh less than 87 grams or more than 93 grams.

For more on the normal distribution, you can check brainly.com/question/24663213

4 0

2 years ago