Question

Hi! can i get some help with this question! :)

Answer 1

Hi there!

$\large\boxed{log_b3b = 1.8397}$

Keep in mind the following log property:

logₓab = logₓa + logₓb

Thus:

$log_{b}3b = log_{b}3 + log_{b}b$

We know the value of log_b3, and a log with the same values for the base equals 1. Thus:

$log_b3b = 0.8397 + 1 = 1.8397$