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RoseWind [281]
3 years ago
14

Help is all I need..

Mathematics
2 answers:
Solnce55 [7]3 years ago
7 0

Answer:

{(x - 1)}^{2}   = 16 \\ x - 1  =  |4| \\ x  =  |4|   + 1

x = +4 +1

x = +5

and

x = -4 + 1

x = -3

Sladkaya [172]3 years ago
5 0

The answer is 5, enjoy

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I have 7 hundreds blocks, 5 tens blocks, and 8 ones blocks. I use my blocks to model two 3-digit numbers. What could my two numb
lawyer [7]
There 7 blocks of hundreds which means each such block is equivalent to 100.
There are 5 blocks of tens, which means each such block is equivalent to 10.
There are 8 blocks of ones, which means each such block is equivalent to 1.

The total of these blocks will be = 7(100) + 5(10) + 8(10) = 758

We can make several two 3-digit numbers from these blocks. An example is listed below:

Example:
Using 3 hundred block, 2 tens blocks and 4 ones block to make one number and remaining blocks to make the other number. The remaining blocks will be 4 hundred blocks, 3 tens blocks and 4 ones blocks
The two numbers we will make in this case are:

1st number = 3(100) + 2(10) + 4(1) = 324
2nd number = 4(100) + 3(10) + 4(1) = 434

The sum of these two numbers is  = 324 + 434 = 758
i.e. equal to the original sum of all blocks.

This way changing the number of blocks in each place value, different 3 digit numbers can be generated. 
5 0
3 years ago
HELP!! 100 POINTS!!
NNADVOKAT [17]

Answer:

x=9 x=-1

Step-by-step explanation:

x²-8x-9=0    a=1 b=-8 c=-9

you have to use the quadratic formula to get the values.

5 0
3 years ago
Read 2 more answers
Help me with this algebra nation problem
Sergio [31]

Answer:

  $295,245

Step-by-step explanation:

Each year the value is 0.9 times what it was the year before. After 5 years, the value is ...

  $500,000 × 0.9^5 = $295,245

6 0
3 years ago
PLEASE SOLVE, ITS REALLY EASY, AND IM ON A TIMER..... EEEEEEE
mart [117]

Answer:

What are the choices? How are we supposed to solve it? Seriously man

Step-by-step explanation:

7 0
3 years ago
Let f(x) = 7x^2-5x+3 and g(x) = 2x^2+4x-6
Troyanec [42]

Answer:

\large\boxed{A.\ f(x)+g(x)=9x^2-x-3}\\\boxed{B.\ f(x)-g(x)=5x^2-9x+9}\\\boxed{g(x)-f(x)=-5x^2+9x-9}

Step-by-step explanation:

f(x)=7x^2-5x+3,\ g(x)=2x^2+4x-6\\\\A:\\f(x)+g(x)=(7x^2-5x+3)+(2x^2+4x-6)\\f(x)+g(x)=7x^2-5x+3+2x^2+4x-6\qquad\text{combine like terms}\\f(x)+g(x)=(7x^2+2x^2)+(-5x+4x)+(3-6)\\f(x)+g(x)=9x^2-x-3

B:\\f(x)-g(x)=(7x^2-5x+3)-(2x^2+4x-6)\\f(x)+g(x)=7x^2-5x+3-2x^2-4x+6\qquad\text{combine like terms}\\f(x)-g(x)=(7x^2-2x^2)+(-5x-4x)+(3+6)\\f(x)+g(x)=5x^2-9x+9

C:\\g(x)-f(x)=(2x^2+4x-6)-(7x^2-5x+3)\\g(x)-f(x)=2x^2+4x-6-7x^2+5x-3\qquad\text{combine like terms}\\g(x)-f(x)=(2x^2-7x^2)+(4x+5x)+(-6-3)\\g(x)-f(x)=-5x^2+9x-9

3 0
3 years ago
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