13000-5600=7400...that's about it, just multiply then subtract
Step-by-step explanation:
lo siento much solo si fuera Buena con matimaticas.
Answer:B
Step-by-step explanation:
Answer:
Quantity of heat needed (Q) = 722.753 × 10³
Step-by-step explanation:
According to question,
Mass of water (m) = 40 kg
Change in temperature ( ΔT) = 18°c
specific heat capacity of water = 4200 j kg^-1 k^-1
The specific heat capacity is the amount of heat required to change the temperature of 1 kg of substance to 1 degree celcius or 1 kelvin .
So, Heat (Q) = m×s×ΔT
Or, Q = 40 kg × 4200 × 18
or, Q = 3024 × 10³ joule
Hence, Quantity of heat needed (Q) = 3024 × 10³ joule
In calories 4.184 joule = 1 calorie
So, 3024 × 10³ joule = 722.753 × 10³
14.99*.12=1.80
14.99-1.8=13.19
13.19*.0625=.94
13.19+.94=14.13
final price 14.13
