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satela [25.4K]
2 years ago
6

In 2000, the total population of the U.S. was 281.4 million people. In 2010, it was 308.7 million people. What is the average ra

te of change in the total population over this time period?
2.73 million people per year


27.3 million people per year



13.6 million people per year



1.36 million people per year
Mathematics
1 answer:
kifflom [539]2 years ago
5 0

Answer:

2.73 million people per year

Step-by-step explanation:

Turn sentences into coordinates/points:

In 2000, 281.4 million people

  • (x₁, y₁) = (2000, 281.4)

In 2010, 308.7 million people

  • (x₂, y₂) = (2010, 308.7)

Rate of population per year:

\sf \dfrac{y_2 - y_1}{x_2- x_1} \ \  where \ (x_1 , \ y_1), ( x_2 , \ y_2) \ are \ points

\rightarrow \sf \dfrac{308.7-281.4}{2010-2000}

\rightarrow \sf 2.73 \ million \ people

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Urgent please help quick!!!
Radda [10]

Answer:

x=-1\\y=-1

Step-by-step explanation:

5x+5y=-10\\3x-7y=4

Let's solve the first equation for either x or y. I'll do it for x.

5x+5y=-10

Begin by subtracting 5y.

5x=-5y-10

Now divide by 5.

x=\frac{-5y}{5}-\frac{10}{5}

Simplify:

x=-y-2

Now substitute x in the second equation for this value.

3x-7y=4\\3(-y-2)-7y=4

Distribute;

-3y-6-7y=4

Add 6

-3y-7y=4+6

Combine like terms;

-10y=10

Divide by -10.

y=\frac{10}{-10}\\ y=-1

-----------------------------------------------------------------------------------------------------------

Take this value of y and replace it in the first equation to find the value of x.

5x+5y=-10\\5x+5(-1)=-10\\5x-5=-10\\5x=-10+5\\5x=-5\\x=\frac{-5}{5}\\ x=-1

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3 years ago
Consider the following theorem and proof.Theorem: The number âš2 is not rational number.Proof: Let's suppose âš2 is a rational n
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Answer:

The statement "Both of the numbers a and b cannot be even." is justified by the fact that a/b is simplified lowest terms

Step-by-step explanation:

We need to  show that the √2 is an irrational number.

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First take the given options :

Option a : √2 is a rational number

√2 being an rational or irrational has no relation of a and b to be even or odd. So, this option is rejected.

Option B : a/b is simplified lowest terms

This shows that a and b are not even because if a and b are even then a/b can be simplified in other lowest term.

Option c : √2 is a irrational number

Similarly, By using the inverse part of Option A, option c is also rejected.

Option d : The fact that b divides a evenly

This only shows that the a is even. This does not give any idea about b is even or not. So option D is also rejected.

Option E : The fact that a and b are whole numbers

This fact does not imply that the a and b are even or odd. So option E is also rejected.

Hence, The statement "Both of the numbers a and b cannot be even." is justified by the fact that a/b is simplified lowest terms

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Step-by-step explanation:

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