To get the solution, we are looking for, we need to point out what we know.
1. We assume, that the number 112 is 100% - because it's the output value of the task.
2. We assume, that x is the value we are looking for.
3. If 112 is 100%, so we can write it down as 112=100%.
4. We know, that x is 200% of the output value, so we can write it down as x=200%.
5. Now we have two simple equations:
1) 112=100%
2) x=200%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
112/x=100%/200%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.
7. Solution for what is 200% of 112
112/x=100/200
(112/x)*x=(100/200)*x - we multiply both sides of the equation by x
112=0.5*x - we divide both sides of the equation by (0.5) to get x
112/0.5=x
224=x
x=224
now we have:
200% of 112=224
●I tried my best I was never good with percentages my least favorite.... Please let me know if you got it wrong. If you do I'm sorry.
Answer:

Step-by-step explanation:
Given a circle centre J
Let the radius of the circle =r
LK is tangent to circle J at point K
From the diagram attached
Theorem: The angle between a tangent and a radius is 90 degrees.
By the theorem above, Triangle JLK forms a right triangle with LJ as the hypotenuse.
Using Pythagoras Theorem:

The length of the radius, 
Answer:
148.75
Step-by-step explanation:
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Answer:
b = 6.79
Step-by-step explanation:
Data provided:
logb(5) = 0.84
Now,
From the properties of log function
logₓ (z)=
(where the base of the log is equal for both numerator and the denominator)
also,
log(xⁿ) = n × log(x)
thus,
using the above properties, we can deduce the results as:
logₓ(y) = n is equivalent to y = xⁿ
Thus,
logb(5) = 0.84
⇒
= 0.84
or
log(5) = 0.84 × log(b)
or
log(5) =
(as log(xⁿ) = n × log(x) )
taking the anti-log both sides
we get
5 =
or
b = 6.79
Answer:
4th choice: I and IV only
Step-by-step explanation:
Change the form of the given equation to standard form.
y = -2/3 x + 2
3y = -2x + 6
2x + 3y = 6
Now compare this equation with the 4 choices.
Any equation that has the same x- and y-terms but a different constant term is parallel.
I. is parallel.
II. and III. are not parallel.
Look at IV.:
4x + 6y = 3
Divide both sides by 2:
2x + 3y = 3/2
IV. is also parallel.
Answer: 4th choice: I and IV only