Answer:
The answer is A.
Step-by-step explanation:
You have to add up both polynomials together :
A = 7x² + 3xy
B = -3xy
A + B = 7x² + 3xy + (-3xy)
= 7x² + 3xy - 3xy
= 7x²
Answer:
0.81 = 81% probability that a randomly selected student is taking a math class or an English class.
0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class
Step-by-step explanation:
We solve this question working with the probabilities as Venn sets.
I am going to say that:
Event A: Taking a math class.
Event B: Taking an English class.
77% of students are taking a math class
This means that 
74% of student are taking an English class
This means that 
70% of students are taking both
This means that 
Find the probability that a randomly selected student is taking a math class or an English class.
This is
, which is given by:

So

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.
Find the probability that a randomly selected student is taking neither a math class nor an English class.
This is

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class
If Sin 60 = √3 / 2
Then, Cos 60 = ?
Well, we know :
Sin^2x + Cos^2x = 1
Let X = 60°
That is,
Sin^2(60) + Cos^2(60) = 1
(√3 / 2)^2 + Cos^2(60) = 1
3 / 4 + Cos^2(60) = 1
Cos^2(60) = 1 - 3/4
Cos^2(60) = 4/4 - 3/4
Cos^2(60) = (4-3)/4
Cos^2(60) = 1/4
Cos(60) = √(1/4)
Cos(60) = √1 / √4
Cos(60) = 1 / 2
This's answer right to the your question.
Using the distance formula I got 10.81665383 : 10.82
Answer:
y=17
Step-by-step explanation: