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Ludmilka [50]
3 years ago
15

If Sally has 10 apples and eats 2 how many does she have left​

Mathematics
1 answer:
lions [1.4K]3 years ago
6 0

Answer:

8

Step-by-step explanation:

10 - 2 = 8

But then again it could be 10 because technically she still has the other two, it's just that they're in her stomach :)

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Plss answer i will give brainliest
Kobotan [32]

Answer:

10 desserts

Step-by-step explanation:

For this question, in order to find all the combinations of desserts, you need to multiply the sizes, flavors, and toppings together.

See:

Sizes * Flavors * Toppings = 2 * 1 * 5 = 10

10 desserts

8 0
3 years ago
Read 2 more answers
Rectangle KLMN has vertices K(-5,6), L(-2,9), M(6, 1), and N(3,-2). Determine and state the coordinates of the point of intersec
Firdavs [7]

Answer:

(0.5,3.5)

Step-by-step explanation:

First, we can draw the image, as shown. The diagonals in the rectangle are the following lines:

from (-2,9) to (3,-2)

from (-5, 6) to (6,1)

To find where they intersect, we can start by making an equation for the lines. For an equation y=mx+b, m represents the slope and b represents the y intercept, or when x=0

For the first line, from (-2,9) to (3,-2), we can calculate the slope by calculating the change in y/change in x = (y₂-y₁)/(x₂-x₁). If (3,-2) is (x₂,y₂) and (-2,9) is (x₁,y₁), our slope is

(-2-9)/(3-(-2)) = -11/5

Therefore, our equation is

y= (-11/5)x + b

To solve for b, we can plug a point in, like (3,-2). Therefore,

-2=(-11/5)*3+b

-2=-33/5+b

-10/5=-33/5+b

add 33/5 to both sides to isolate b

23/5=b

Our equation for one diagonal is therefore y=(-11/5)x+23/5

For the second line, from (-5, 6) to (6,1), if (6,1) is (x₁,y₁) and (-5,6) is (x₂,y₂), the slope is (1-6)/(6-(-5)) = -5/11 . Plugging (6,1) into the equation y=(-5/11)x+b, we have

1=(-5/11)*6+b

11/11 = -30/11 + b

add 30/11 to both sides to isolate b

41/11 = b

our equation is

y = (-5/11) x + 41/11

Our two equations are thus

y = (-5/11) x + 41/11

y=(-11/5)x+23/5

To find where they intersect, we can set them equal to each other

(-11/5)x+23/5 = y = (-5/11) x + 41/11

(-11/5)x + 23/5 = (-5/11)x + 41/11

subtract 23/5 from both sides as well as add 5/11 to both sides to make one side have only x values and their coefficients

(-11/5)x + (5/11)x = 41/11-23/5

11*5 = 55, so 55 is one value we can use to make the denominators equal.

(-11*11/5*11)x+(5*5/11*5)x=(41*5/11*5)-(23*11/5*11)

(-121/55)x+(25/55)x = (205/55) - (253/55)

(-96/55)x = (-48/55)

multiply both sides by 55 to remove the denominators

-96x=-48

divide both sides by -96 to isolate x

x=-48/-96=0.5

plug x=0.5 into a diagonal to see the y value of the intersection

(-11/5)x + 23/5 = y = (-11/5)* 0.5 + 23/5 = 3.5

3 0
3 years ago
The track is 3/5 of a mile long. If Tyrone jogged around it twice, how far did he run?
Charra [1.4K]
6/5 of a mile or a mile and 1/5 they are the same
6 0
3 years ago
Help please if you can then thank you so much if you can't see number 4 and 5 then here.
sergij07 [2.7K]

Answer:

2) A- 8h 15m

3) C- 6h 59m

4) A- 37m

5) B- 1h 2m


5 0
4 years ago
Read 2 more answers
Find the fourth point of a parallelogram given the first three (more than one correct answer is possible): (0,6), (5, -1) and (3
inysia [295]

Answer:

The fourth point of the parallelogram is one point among (-2,2), (2,10) and (8,-12).

Step-by-step explanation:

Given information: The first three vertices of parallelogram are (0,6), (5, -1) and (3,-5).

Let fourth point of the parallelogram is (a,b).

Diagonals of a parallelogram bisect each other. It means midpoint of both diagonals are same.

Midpoint formula:

Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Case 1: If the point (0,6), (5, -1) and (3,-5) are consecutive, then pairs of opposite vertices are (0,6) and (3,-5), (5,-1) and (a,b).

(\frac{0+3}{2},\frac{6-5}{2})=(\frac{5+a}{2},\frac{-1+b}{2})

(\frac{3}{2},\frac{1}{2})=(\frac{5+a}{2},\frac{-1+b}{2})

On comparing both sides, we get

\frac{3}{2}=\frac{5+a}{2}

3=5+a

a=-2

\frac{1}{2}=\frac{-1+b}{2}

1=-1+b

b=2

It means the fourth point of the parallelogram is (-2,2).

Case 2: If the point (0,6), (5, -1) and (3,-5) are not consecutive, then pairs of opposite vertices are (0,6) and (5,-1), (3,-5) and (a,b).

(\frac{0+5}{2},\frac{6-1}{2})=(\frac{3+a}{2},\frac{-5+b}{2})

(\frac{5}{2},\frac{5}{2})=(\frac{3+a}{2},\frac{-5+b}{2})

On comparing both sides, we get

\frac{5}{2}=\frac{3+a}{2}

5=3+a

a=2

\frac{5}{2}=\frac{-5+b}{2}

5=-5+b

b=10

It means the fourth point of the parallelogram is (2,10).

Case 3: If the point (0,6), (5, -1) and (3,-5) are not consecutive, then pairs of opposite vertices are (5,-1) and (3,-5), (0,6) and (a,b).

(\frac{5+3}{2},\frac{-1-5}{2})=(\frac{0+a}{2},\frac{6+b}{2})

(\frac{8}{2},\frac{-6}{2})=(\frac{a}{2},\frac{6+b}{2})

On comparing both sides, we get

\frac{8}{2}=\frac{a}{2}

8=a

\frac{-6}{2}=\frac{6+b}{2}

-6=6+b

b=-12

It means the fourth point of the parallelogram is (8,-12).

5 0
4 years ago
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