Answer:
Amount invested at 8% is $9000 and amount invested at 18% is $21000.
Step-by-step explanation:
Let amount invested at 8% be x.
Let amount invested at 18% be y.
We get the 1st equation as:
........(1)
We get the second equation as:
=> 
or getting rid of the decimal by multiplying by 100 on both sides.
........(2)
Multiplying (1) by 8 and subtracting from (2) we get
So, y = 21000
And 
So, x = 9000
Therefore, amount invested at 8% is $9000 and amount invested at 18% is $21000.
784 divide by 7 is 112 so answer 112
Answer:
b = 6.79
Step-by-step explanation:
Data provided:
logb(5) = 0.84
Now,
From the properties of log function
logₓ (z)= 
(where the base of the log is equal for both numerator and the denominator)
also,
log(xⁿ) = n × log(x)
thus,
using the above properties, we can deduce the results as:
logₓ(y) = n is equivalent to y = xⁿ
Thus,
logb(5) = 0.84
⇒ 
= 0.84
or
log(5) = 0.84 × log(b)
or
log(5) = 
(as log(xⁿ) = n × log(x) )
taking the anti-log both sides
we get
5 = 
or
b = 6.79
Hey!
Find 80% of the original cost:
1.25 * 80% = 1
1.25 + 1 = 2.25
ANSWER: $2.25.
Answer:
$270
Step-by-step explanation:
Simply take the per hour rate and multiply it by the number of hours.
6.75 X 40 = 270
