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hammer [34]
2 years ago
6

Will award brainliest to correct answer!

Mathematics
1 answer:
Artyom0805 [142]2 years ago
6 0

Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°.

\angle \: ABP =  \frac{180 - 80}{2}  = 50 \degree

Finally, let point K be the intersection between segments BC and PQ, and let's note that the triangle PQB is a right isosceles triangle, since all the angles in a square are equal to 90°, and the two triangles APB and BQC are congruent.

Therefore, the angle BKQ is equal to 180-50-45=85°.

Of course angle BKP=180-85=95°.

Hope this helps :)

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