Answer:
20kg of $0.89 candy
10kg of $1.10 candy
Step-by-step explanation:
Candy 1 = 0.89 per kg
Candy 2 = 1.10 per kg
Total kilogram, kg = 30
Let candy 1 = x ; candy 2 = (30 - x) ;
0.89x + 1.10(30 - x) = 0.96(30)
0.89x + 33 - 1.10x = 28.8
0.89x - 1.10x = 28.8 - 33
-0.21x = - 4.2
x = 4.2 / 0.21
x = 20
20kg of $0.89 candy
(30 - x) = (30 - 20) = 10kg
10kg of $1.10 candy
Answer:1) 0.0416 2).03 3) .05
Step-by-step explanation:you divid the distance by the times
Answer:
<h3>The 12th term is 1771470</h3>
Step-by-step explanation:
Since the above sequence is a geometric sequence
An nth term of a geometric sequence is given by
where a is the first term
r is the common ratio
n is the number of terms
From the question
a = 10
To find the common ratio divide the previous term by the next term
That's
r = 30/10 = 3 or 90/30 = 3 or 270/90 = 3
Since we are finding the 12th term
n = 12
So the 12th term is
<h3>A(12) = 1771470</h3>
Hope this helps you
Answer:
0.50 ,1/2 as a fraction 1/2
Step-by-step explanation:
Given that the book value of the automobile that was purchased is 30,000 and is to be depreciated for 3 years using MACRS method of depreciation the value of the automobile at the end of the year is 8,640 dollars. This is computed by summing up the depreciation for the firswt 3 years which is equal to 71.2 per cent less 100 then it will be multiply to 30,000.
