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shtirl [24]
3 years ago
9

Choose 3 values that would make thi inequalitie true 28+x>42

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
4 0

9514 1404 393

Answer:

  14.01, 493, 87

Step-by-step explanation:

Subtracting 28 from both sides tells you the range of values you need to be looking at.

  28 + x > 42

  x > 14

Any values more than 14 will make the inequality true. Three of them are ...

  14.01, 493, 87

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Answer:

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Step-by-step explanation:

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it might be clearer when I show you:

f(x) = (x^2 + 1)(x^3 + 1)\\f'(x) = (2x)(x^3 + 1) + (x^2 + 1)(3x^2)\\Simplify:\\f'(x) = 2x^4 + 2x + 3x^4 + 3x^2 = 5x^4 + 3x^2 + 2x\\

If you are not familiar with this rule you can first write out the function and then use the basic rule:

f(x) = (x^2 +1)(x^3+1) = x^5 + x^2 + x^3 + 1\\f'(x) = 5x^4 + 2x + 3x^2

If you need any further help please say so in the comments! I hope this helps! If the steps seem complicated, I suggest you could revise expanding brackets (the first step of the second method) and the basic rules of deriving, but feel free to reach out if you struggle afterwards still

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