Choose 3 values that would make thi inequalitie true 28+x>42

Mathematics

1 answer:

Y_Kistochka [10]2 years ago

4 0

9514 1404 393

Answer:

14.01, 493, 87

Step-by-step explanation:

Subtracting 28 from both sides tells you the range of values you need to be looking at.

28 + x > 42

x > 14

Any values more than 14 will make the inequality true. Three of them are ...

14.01, 493, 87

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Karo-lina-s [1.5K]

$\text{The scientific notation:}\\\\a\times10^n\\\\1\leq a$

$a.\\(5\times10^3)\times(3.5\times10^{-1})=(5\times3.5)\times(10^3\times10^{-1})\\\\=15.75\times10^{3+(-1)}=15.75\times10^2=1.575\times10\times10^2\\\\=1.575\times10^{1+2}=\boxed{1.575\times10^3}$

$b.\\(8\times10^2)\div(4\times10^3)=(8\div4)\times(10^2\div10^3)=2\times10^{2-3}\\\\=\boxed{2\times10^{-1}}$

$c.\\(6\times10^{-3})^2=6^2\times(10^{-3})^2=36\times10^{-3\cdot2}=36\times10^{-6}=3.6\times10\times10^{-6}\\\\=3.6\times10^{1+(-6)}=\boxed{3.6\times10^{-5}}$