1. First, you must find the constant of variation (k). The problem indicates that t<span>he base of each triangle varies inversely with the height. So, this can be represented as below:
</span>
B=k/H
B is the base of the triangle (B=10).
H is the height of the triangle (H=6).
k is the constant of variation.
2. When you clear "k", you obtain:
B=k/H
k=BxH
k=10x6
k=60
3. Now, you have:
B=60/H
4. You can give any value to "H" and you will obtain the base of the second triangle.
5. If H=12, then:
B=60/H
B=60/12
B=5
6. Therefore, <span>the possible base and height of a second triangle is:
</span>
B=5
H=12
8x9=72 ft squared
4x3=12 ft squared
72+12=84 ft squared
Y = x
y = -2/3x + 5
x = -2/3x + 5
x + 2/3x = 5
3/3x + 2/3x = 5
5/3x = 5
x = 5 * 3/5
x = 15/5 reduces to 3
y = x
y = 3
so ur answer is (3,3)
Answer:
is you are not adding in the 24 then 40 if you are adding in the 24 then 64
Step-by-step explanation:
I think i may know what your asking, is it a angle at a point? I don’t know what your asking so that a guess based off what i know from your question.
