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2 years ago

Angela’s and Ben’s Cell Phone Plan

Mathematics

1 answer:

Ulleksa [173]2 years ago

3 0

Answer:

lol wdym.…......…..........

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Answer the question. Show work

RideAnS [48]

We just need to get the perimeter of the backyard.

Whole rectangle: length = 7ft ; width = 5 ft

Perimeter = 2(7+5) = 2(12) = 24 ft

7 0

2 years ago

Connie keeps her sports card collection in a 54-page book. Each page has 9 slots for cards.

vesna_86 [32]

Answer:

324 slots.

Step-by-step explanation:

If there is 9 slots per page, and 18 pages in the 54 page book are taken up by football cards, that leaves you with 36 pages left. Again, 9 slots per page, so you multiply 9 x 36 and get 324 slots available for baseball cards.

7 0

2 years ago

Read 2 more answers

A soccer field is a rectangle 160 meters wide and 120 meters long. The coach asks players to run from one corner to the corner d

Irina-Kira [14]

Answer:

200 meters

Step-by-step explanation:

a² + b² = c²

c² = 120² + 160²

c² = 14,400 + 25,600

c² = 40,000

√(c²) = √(40,000)

c = 200

Answer: 200 meters

8 0

2 years ago

Can anyone help me with this question please:

ladessa [460]

The problem is asking us to isolate B. The given equation is solved for P, and we need to rearrange it for B.

First we need to square both sides. This will cancel out the square root on the right side.

P^2 = E + A^2/B^2

Next, subtract E from both sides.

P^2 - E = A^2/B^2

Next we need to get the B^2 out of the denominator. Multiply both sides by B^2.

B^2(P^2 - E) = A^2

Next divide both sides by (P^2 - E).

B^2 = A^2/(P^2 - E)

Lastly, take the square root of both sides.

B = sqrt(A^2/(P^2 - E))

3 0

2 years ago

Simplify each expression. Assume that all variables are positive.

kozerog [31]

Q1. The answer is $\frac{8x^{3}y^{6} }{27}$

$( \frac{16 x^{5} y^{10}}{81x y^{2} } )^{ \frac{3}{4} }= ( \frac{16}{81}* \frac{ x^{5} }{x}* \frac{ y^{10} }{y^{2}} )^{ \frac{3}{4} } \\ \\ 
 \frac{ x^{a} }{ x^{b} }= x^{a-b} \\ \\ 
( \frac{16}{81}* \frac{ x^{5} }{x}*\frac{ y^{10} }{y^{2}} )^{ \frac{3}{4} }}=( \frac{16}{81 }* x^{5-1}* y^{10-2})^{ \frac{3}{4} }=( \frac{16}{81 }* x^{4}* y^{8})^{ \frac{3}{4} }= \\ \\ = (\frac{16}{18} )^{ \frac{3}{4} }*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} }=$
$\frac{(16)^{ \frac{3}{4} }}{(18)^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} }=\frac{( 2^{4} )^{ \frac{3}{4} }}{( 3^{4} )^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} } \\ \\ 
 (x^{a} )^{b} = x^{a*b} \\ \\ 
\frac{( 2^{4} )^{ \frac{3}{4} }}{( 3^{4} )^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} } = \frac{ 2^{4* \frac{3}{4} } }{ 3^{4* \frac{3}{4} } } * x^{4* \frac{3}{4} } * y^{8*\frac{3}{4}} = \frac{ 2^{3} }{ 3^{3} } * x^{3} *y^{6} =$
$= \frac{8x^{3}y^{6} }{27}$

Q2. The answer is 1/16

$(-64) ^ \frac{-2}{3} =(-1* 2^{6} ) ^ \frac{-2}{3}=(-1)^ \frac{-2}{3} *(2^{6} ) ^ \frac{-2}{3} \\\\x^{-a} = \frac{1}{ x^{a} } \\\\(-1)^ \frac{-2}{3} *(2^{6} ) ^ \frac{-2}{3} = \frac{1}{(-1)^ \frac{2}{3}} *\frac{1}{(2^{6})^ \frac{2}{3}} \\ \\ (x^{a} )^{b}=x^{a*b} \\\\x^{ \frac{a}{b} = \sqrt[b]{ x^{a} } } \\ \\ 
$
$\frac{1}{(-1)^ \frac{2}{3}} *\frac{1}{2^{6*\frac{2}{3}}} = \frac{1}{ \sqrt[3]{(-1)^{2} } } * \frac{1}{ 2^{4} } = \frac{1}{ \sqrt[3]{1} } * \frac{1}{16} = \frac{1}{1} * \frac{1}{16}= \frac{1}{16}$

Q3. The answer is $a^{ \frac{7}{6} }$

$a^{ \frac{2}{3} } * a^{ \frac{1}{2} } \\ \\ 
 x^{a}* x^{b} =x^{a+b} \\ \\ 
a^{ \frac{2}{3} } * a^{ \frac{1}{2} }= a^{ \frac{2}{3} + \frac{1}{2} } =a^{ \frac{2*2}{3*2} + \frac{1*3}{2*3} }=a^{ \frac{4}{6} + \frac{3}{6} }=a^{ \frac{4+3}{6} }=a^{ \frac{7}{6} }$

7 0

2 years ago