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2 years ago

I need help asap plz

Mathematics

1 answer:

IgorC [24]2 years ago

7 0

Answer:light blue

Step-by-step explanation:

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Help fill in the blanks no

DerKrebs [107]

Answer:

Here is the full proof:

AC bisects ∠BCD Given

∠CAB ≅ ∠CAD Definition of angle bisector

DC ⊥ AD Given

∠ADC = 90° Definition of perpendicular lines

BC ⊥ AB Given

∠ABC = 90° Definition of perpendicular lines

∠ADC ≅ ∠ABC Right angles are congruent

AC = AC Reflexive property

ΔCAB ≅ ΔCAD SAA

BC = DC CPCTC

7 0

2 years ago

The table below shows some inputs and outputs of the invertible function f with domain all real numbers.

Ratling [72]

Answer:

${f}^{ - 1} (f(93)) = 93$

$f(f(7)) = - 15$

Step-by-step explanation:

A function and its inverse has the following properties

${f}^{ - 1} (f(x)) = x$

This implies that;

${f}^{ - 1} (f(93)) = 93$

From the table,

$f(7) = - 6$

This means that:

$f(f(7)) = f( - 6)$

$f(f(7)) = - 15$

Note that: f(7) means the value of f(x) when x=7.

From the table f(x)=-6 when x=7.

That is why f(7)=-6.

5 0

3 years ago

A bag contains different colored candies. There are 50 candies in the bag, 28 are red, 10 are blue, 8 are green and 4 are yellow

Mrrafil [7]

Answer:

$\displaystyle \frac{54}{5405}$ .

Step-by-step explanation:

How many unique combinations are possible in total?

This question takes 5 objects randomly out of a bag of 50 objects. The order in which these objects come out doesn't matter. Therefore, the number of unique choices possible will the sames as the combination

$\displaystyle \left(50\atop 5\right) = 2,118,760$ .

How many out of that 2,118,760 combinations will satisfy the request?

Number of ways to choose 2 red candies out a batch of 28:

$\displaystyle \left( 28\atop 2\right) = 378$ .

Number of ways to choose 3 green candies out of a batch of 8:

$\displaystyle \left(8\atop 3\right)=56$ .

However, choosing two red candies out of a batch of 28 red candies does not influence the number of ways of choosing three green candies out of a batch of 8 green candies. The number of ways of choosing 2 red candies and 3 green candies will be the product of the two numbers of ways of choosing

$\displaystyle \left( 28\atop 2\right) \cdot \left(8\atop 3\right) = 378\times 56 = 21,168$ .

The probability that the 5 candies chosen out of the 50 contain 2 red and 3 green will be:

$\displaystyle \frac{21,168}{2,118,760} = \frac{54}{5405}$ .

3 0

2 years ago

{(-3.7).(-5, -8), (-6, -1). (-9, -1), (0, -3) }

zhenek [66]

Answer:

The domain is the set of all the values of x, so it would be -3, -5, -6, -9, 0. The range would be every set of y, so it would be 7, -8, -1, -3. Finally, this relation is indeed a function.

Domain: -3, -5, -6, -9, 0

Range: 7, -8, -1, -3

Is it a function? Yes

4 0

3 years ago

nelson used 35% of his savings account for his class trip in May. if he used $140 from his savings account while on his class tr

Liono4ka [1.6K]

Answer:

He had 189 dollars

Step-by-step explanation:

35% of 140 is 49

140 plus 49 is 189

8 0

2 years ago