The tower is 61.65 meters tall.
<u>SOLUTION:
</u>
Given that, a pole that is 2.5 m tall casts a shadow that is 1.47 m long.
At the same time, a nearby tower casts a shadow that is 36.25 m long.
We have to find height of the tower.
Now, we know that,

Then, (let it be) n meter tall
36.25 long shadow
So, by cross multiplication method,

This can be written as,

Cross multiplications steps: (To find Single Variable)
- Multiply the numerator of the left-hand fraction by the denominator of the right-hand fraction.
- Multiply the numerator of the right-hand fraction by the denominator of the left-hand fraction.
- Set the two products equal to each other.
- Solve for the variable.
Step-by-step explanation:
Tn=ar^(n-1)
r=-10/-5=2
a=-5
Tn=-5×(2)^(n-1)
Tn=-5•(2)^(n-1)
an=5•(2)^(n-1)
(-2,6) iissssssss the answer
700ml=23.6698fl
64-23.6698=40.3302
40.3302fl
Those are adjacent angles. They equal 180 degrees.
10x-20+6x+8= 180
16x-12=180
Add 12.
16x= 192
x=12
I hope this helps!
~kaikers