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Dennis_Churaev [7]
2 years ago
9

A boy is 6 years older than his sister. In three years time he will be twice her age. What

Mathematics
1 answer:
Masja [62]2 years ago
3 0

Answer:

12 years old

18-6=12

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If the public debt of the United States of Apex is 9,529,034,179,824,022 Apex dollars and its gross domestic product (GDP) is 16
aivan3 [116]
To compute for the debt-to-GDP ratio, we just have to divide the debt given in this item by the GDP and convert the quotient to percentage. That is,
                debt-to-GDP ratio = (9,529,034,179,824,022)/                              (16,247,683,987,248,007) x 100%
                debt-to-GDP ratio = 58.65%
Thus, the answer is FALSE. 
8 0
3 years ago
Read 2 more answers
PLEASE HELP!! Write an equation of g(x) that represents an exponential base “e” parent function with the following transformatio
Montano1993 [528]

Answer:

g(x) = 12 {e}^{ - x - 7}

Step-by-step explanation:

The parent function is

g(x) = e {}^{x}

First it is asked to reflect over the y axis so using the rule

g(x) = g( - x)

Our function looks like

g(x) = e {}^{ - x}

Then we are asked to shift the equation to the right 7. When shifting to the right or move the x axis, instead of adding 7 we would want to subtract 7 since the x axis is the independent variable and we must respect the y axis which is the dependent so using the rule

g(x) = g(x - h)

When subtracting a 7 it looks like now

where h is the number we move . Now we are asked to apply a vertical stretch of 12. Since vertical stretch refers to the y axis, we are just going to multiply the function by 12 using the rule

g(x) = a \times g(x)

where a is the vertical stretch. So now it would look like

g(x) = 12 {e}^{ - x - 7}

4 0
3 years ago
Can you help me find t value in this problem?
Eduardwww [97]

we have a maximum at t = 0, where the maximum is y = 30.

We have a minimum at t = -1 and t = 1, where the minimum is y = 20.

<h3>How to find the maximums and minimums?</h3>

These are given by the zeros of the first derivation.

In this case, the function is:

w(t) = 10t^4 - 20t^2 + 30.

The first derivation is:

w'(t) = 4*10t^3 - 2*20t

w'(t) = 40t^3 - 40t

The zeros are:

0 = 40t^3 - 40t

We can rewrite this as:

0 = t*(40t^2 - 40)

So one zero is at t = 0, the other two are given by:

0 = 40t^2 - 40

40/40 = t^2

±√1 = ±1 = t

So we have 3 roots:

t = -1, 0, 1

We can just evaluate the function in these 3 values to see which ones are maximums and minimums.

w(-1) = 10*(-1)^4 - 20*(-1)^2 + 30 = 10 - 20 + 30 = 20

w(0) = 10*0^4 - 20*0^2 + 30    = 30

w(1) =  10*(1)^4 - 20*(1)^2 + 30 =  20

So we have a maximum at x = 0, where the maximum is y = 30.

We have a minimum at x = -1 and x = 1, where the minimum is y = 20.

If you want to learn more about maximization, you can read:

brainly.com/question/19819849

6 0
2 years ago
[20 pts] evaluate the logarithm log(6)1/36​, show work pls!
Delvig [45]

Answer:

\large\boxed{\log_6\dfrac{1}{36}=-2}

Step-by-step explanation:

\text{We know:}\\\\\log_ab=c\iff a^c=b\\\\\log_6\dfrac{1}{36}\qquad\text{use}\ a^{-1}=\dfrac{1}{a}\\\\=\log_636^{-1}=\log_6(6^2)^{-1}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\log_66^{(2)(-1)}=\log_66^{-2}\qquad\text{use}\log_ab^n=n\log_ab\\\\=-2\log_66\qquad\text{use}\ \log_aa=1\\\\=-2(1)=-2

\log_6\dfrac{1}{36}=-2\ \text{because}\ 6^{-2}=\dfrac{1}{6^2}=\dfrac{1}{36}

8 0
3 years ago
Plz help me well mark brainliest!!
vampirchik [111]

Answer : B! As you can see, you can go to the x axis, and go to number 4. Then go down to -2, and you will end up in point B!

5 0
2 years ago
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