The correct answer is B. false.
Determining which color goes first is not random at all - it is a rule in chess that the White player will always start the game first, and will then be followed by the Black player.
The option that best explains why the error occurs is that The program can only use a fixed number of bits to represent integers; the computed sum is greater than the maximum representable value.
<h3>Can programs represent integers?</h3>
An integer value is known to be often listed out in the source code of a program in a way called a sequence of digits that is said to be optionally prefixed with + or −. Note that some programming languages do use other notations, like hexadecimal.
Computers are known to use a a fixed number of bits to show an integer. The most -used bit-lengths for integers are known to be 8-bit, 16-bit, 32-bit or 64-bit.
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Answer:
A Tape Library
Explanation:
A tape library, sometimes called a tape silo, tape robot or tape jukebox, is a storage device that contains one or more tape drives, a number of slots to hold tape cartridges, a barcode reader to identify tape cartridges and an automated method for loading tapes. It Enables faster data migrations, reduce the complexity of and increase the frequency of backups, and streamline governance in a secure and cost-effective way.
Answer:
Be polite and open to ideas
Explanation:
Before going make a list of things you need to know for sure. You could also provide some samples. Make sure you take many notes on what they want! Speak with your client and ask them how and when they want to be updated on progress, some might want to know once a week others may want to receive a progress report every day. Communication is always key and will always help you provide good service.
Hopefully, this helps!
Answer:
2^11
Explanation:
Physical Memory Size = 32 KB = 32 x 2^10 B
Virtual Address space = 216 B
Page size is always equal to frame size.
Page size = 16 B. Therefore, Frame size = 16 B
If there is a restriction, the number of bits is calculated like this:
number of page entries = 2^[log2(physical memory size) - log2(n bit machine)]
where
physical memory size = 32KB which is the restriction
n bit machine = frame size = 16
Hence, we have page entries = 2^[log2(32*2^10) - log2(16)] = 2ˆ[15 - 4 ] = 2ˆ11
