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julsineya [31]
3 years ago
8

Un terreno de 4200 metros cuadrados de superficie se quiere dividir en dos lotes de manera que el lote menor sea tres cuartas pa

rtes del lote mayor, ¿Cuánto debe medir el lote menor? Y ¿Cuánto el lote mayor?
Mathematics
1 answer:
lions [1.4K]3 years ago
4 0

Answer:

El lote menor tendrá 1800 m^2

El lote mayor tendrá 2400 m^2

Step-by-step explanation:

Definamos las variables:

M = superficie del lote mayor

m = superficie del lote menor.

Sabemos que el terreno tiene en total 4200 m^2

Entonces:

M + m = 4200 m^2.

Y queremos que el lote menor sea 3/4 del lote mayor, entonces:

m = (3/4)*M

Podemos reemplazar esto en la ecuación de arriba para obtener:

M + ( (3/4)*M) = 4200 m^2.

Y ahora podemos resolver esto para M

M + (3/4)*M = 4200m^2

M*(1 + 3/4) = 4200m^2

M*(4/4 + 3/4) = 4200 m^2

M*(7/4) = 4200m^2

M = (4/7)*(4200m^2) = 2400m^2

Esto significa que la superficie del mayor lote es 2400 m^2

Y la superficie del menor se puede obtener con la ecuación:

m = (3/4)*M

m = (3/4)*2400m^2 = 1800m^2

La superficie del lote menor es 1800m^2

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