We are given the area of the region under the curve of the function f(x) = 5x + 7 with an interval [1, b] which is 88 square units where b > 1
We need to find the integral of the function f(x) = 5x + 7 with the limits 1 and b
5/2 x^2 + 7x (limits: 1, b)
substitute the limits:
5/2 (1^2) + 7 (1) - 5/2 b^2 + 7b = 0
solve for b
Then after solving for b, this would be your interval input with 1: [1, b].<span />
To solve this question you need to cross multiply
So first do 3(2x+1) = 4(3x-2)
Which gives you 6x+1 = 12x-8
Now you solve it like a normal equation
6x+1 = 12x-8
9 = 6x
3/2 = x
Answer
true
Step-by-step explanation:
It’s 22/3 I think so that’s the answer
68900%
Step-by-step explanation:
wherever the decimal point is you place the percent sign two places over
