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AlekseyPX
3 years ago
13

​Thirty-six percent of customers who purchased products from an​ e-commerce site had orders exceeding 110. If ​17% of customers

have orders exceeding 110 and also pay with the​ e-commerce site's sponsored credit​ card, determine the probability that a customer whose order exceeds 110 will pay with the sponsored credit card.

Mathematics
1 answer:
Dvinal [7]3 years ago
3 0

Answer:

The right solution is "0.5".

Step-by-step explanation:

According to the question,

P(pay with the sponsored credit card | order exceeds $110)

= \frac{P(Pay \ with \ the \ sponsored \ credit\ card\ and\ order\ exceeds\ 110)}{P(order \ exceeds \ 110)}

= \frac{P(A \ and \ B)}{P(A)}

By putting the values, we get

= \frac{0.17}{0.34}

= 0.5

Thus, the above is the right solution.

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Elke lives mile from 1/10school. Haresh lives 2/3 mile from school.
lawyer [7]

Answer: 17/30

Step-by-step explanation:

From the question, Elke lives 1/10 mile from school while Haresh lives 2/3 mile from school.

The closer to school Elke is than Haresh will be:

= 2/3 - 1/10

We can change the fractions to have thesame denominator which will be:

= 2/3 - 1/10

= 20/30 - 3/30

= 17/30

The distance between them is 17/30 miles

5 0
3 years ago
Given that cos(θ)= -√3/4 and tan(θ) > 0, find sin(θ)
BARSIC [14]

Answer:

B. -√13/4

Step-by-step explanation:

cos 0 = -√3/4 => x=-√3 , h=4

tan 0 > 0

y should be on quadrant III

y= √4²-3= √16-3=√13 => -√13

so, sin 0 = y/h = -√13/4

8 0
3 years ago
Read 2 more answers
Which statements are true about rhombuses? Select all that apply.
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Answer:

A, C D

Step-by-step explanation:

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3 0
2 years ago
gary, Heather, and Irene want to find the zeros of the polynomial P(x). They evaluate the polynomial for different values and fi
LenKa [72]

Answer:

The answer is given below

Step-by-step explanation:

A number is said to be a zero of a polynomial if when the number is substituted into the function the result is zero. That is if a is a zero of polynomial f(x), therefore f(a) = 0.

Since  P(−1)=0 P(0)=1 P(2+√3)=0, therefore -1 and 2+√3 are zeros of the polynomial.

Gary is right because there are 2 known zeros of P(x) which are −1 and 2+√3. Also 2 - √3 is also a root. From irrational root theorem, irrational roots are in conjugate pairs i.e. if a+√b is a root, a-√b is also a root.

Heather is not correct because if P(0) = 1, it means that 0 is not a root. It does not mean that 1 is a zero of P(x)

Irene is correct. since P(−1) and P(2+3–√) equal 0, 2 zeros of P(x) are −1 and 2+√3. They may be other zeros of P(x), but there isn't enough information to determine any other zeros of P(x)

8 0
4 years ago
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